MATLAB: Count 1’s in binary

binarycount 1's

Hi,

This is what i want… I have a binary array

001111000000011100000000011111

from here i have to count the number 1 in such way

result: 0,4,0,3,0,5…. how to get this?

Best Answer

If you have the Image Processing Toolbox, it's just two real lines of code, a call to regionprops and a line to extract the lengths from what regionprops returns.

% Create sample binary data.
binaryArray = [0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1]
% Measure lengths of stretches of 1's.
measurements = regionprops(logical(binaryArray), 'Area');
% Convert from structure to simple array of lengths.
allLengths = [measurements.Area]
% If you want 0's in between for some reason:
out = zeros(1, 2*length(allLengths)+1);
out(2:2:end) = allLengths

5000 numbers is no problem. This code can handle millions of them.

Related Solutions

MATLAB: How to find run length consecutive ones and zeros and their occurrence times in a binary sequence in MATLAB

You can use the TEXTSCAN function by specifying delimiters and then use LENGTH function to find the length of each sequence. After that, you can compute the number of occurrences with HIST function as in the example below:

%Creating a binary sequence in a string with no spaces 
s = [1 1 0 0 0 0 0 1 1 1 1 0 1 1 0 1 1 0 1 1 1 0 1 0 1 0 1 0 0 1 1 1];
s = sprintf('%d',s);
%Reading the consequences of 1's from the string by using 0's as delimiters
t1=textscan(s,'%s','delimiter','1','multipleDelimsAsOne',1);
% Converting cell array of cell into a single cell array
d = t1{:};
% Computing the length of each run by going through the array and assigning
% it into 
for k = 1:length(d)
      data(k) = length(d{k});
end
% Using histogram function to compute the number of times for each length
[number_times run_length] = hist(data, [1:max(data)])

To do the same operation for finding run lengths and frequencies of "zeros" instead of "'ones", change the delimiter in the TEXTSCAN function to be '1' instead of '0'.

MATLAB: Decimal to binary conversion of an array

Cell array of character vectors:

>> a = [102,2,3,201,8,9];
>> c = arrayfun(@dec2bin,a,'uni',0);
>> c{:}
ans = 1100110
ans = 10
ans = 11
ans = 11001001
ans = 1000
ans = 1001

Cell array of numeric vectors:

>> c = arrayfun(@(n)dec2bin(n)-'0',a,'uni',0);
>> c{:}
ans =
   1   1   0   0   1   1   0
ans =
   1   0
ans =
   1   1
ans =
   1   1   0   0   1   0   0   1
ans =
   1   0   0   0
ans =
   1   0   0   1

Best Answer

Related Solutions

MATLAB: How to find run length consecutive ones and zeros and their occurrence times in a binary sequence in MATLAB

MATLAB: Decimal to binary conversion of an array

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