MATLAB: Bsxfun – @minus – how to divide by maximum

array

Hello everyone,
I have two arrays:
a = [1; 2; 3]
b = [1; 2; 3; 4]
out = abs(bsxfun(@minus,a,b')./a)
I am getting this:
out = [0    1    2    3
       0.5  0  0.5  1.0
       0.67 0.33 0 0.33]
I am looking for a way to divide not simply by ./a, but to divide by the maximum number in the numerator. So instead of calculating abs(1-3)/1=2 for out(1,3) I would like the calculation to be abs((1-3)/3)=0.67.
Any help is greatly appreciated.

Best Answer

Do do poor job to explain, up to everyone guess
>> a = [3; 5; 1;]
a =
     3
     5
     1
>> b = [3; 2; 3; 4]
b =
     3
     2
     3
     4
>> abs(a-b')./max(a,b')
ans =
         0    0.3333         0    0.2500
    0.4000    0.6000    0.4000    0.2000
    0.6667    0.5000    0.6667    0.7500
>> abs(bsxfun(@minus,a,b'))./bsxfun(@max,a,b')
ans =
         0    0.3333         0    0.2500
    0.4000    0.6000    0.4000    0.2000
    0.6667    0.5000    0.6667    0.7500
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