MATLAB: Add matrix to cell

cell arraysfor loopMATLAB and Simulink Student Suitematrix

i have matrix 25×25, i need reflaction matrix from line no 2 to 25

i was looking at using fliplr but i have a problem,

A=rand(25,25)
B=fliplr(A(2:25)) % only line no 2
C= nan(25,24)
for C=1:24
    C(1,:)=fliplr(A(2:25));
end

this only reflaction in line no 2. to solve it

any comments

Best Answer

I guese you want like this??

A=rand(25,25);
B=fliplr(A(2:25,:)); % only line no 2
C= nan(25,25);
C(2:25, :) = B;    % assign reflection matrix to C where C first line values are NaNs

Related Solutions

MATLAB: How to find ‘numbers’ of unique variable in matrix. How many quantity of variables.

Hi,

To reformulate your question (as I understood it) you would like to be able to return the count of occurrences of each element in a vector. There are multiple ways to do this. One solution would be by using hist and unique functions

x=[2 5 2 52 5 25 2 5 2 22 5 2 5 52 5 55 4 5 5 2 5 5 25 2 5 2 54 5 54 5 2 5 5 5 5 5 5 5 25 2 255 2 5 5 2 55 2 5 5 2 5 5 2 255 2 52 5 2 5 ];
>> [a,b]=hist(x,unique(x))
a =
      17     1    28     1     3     3     2     2     2
b =
       2     4     5    22    25    52    54    55   255

where a(i) is the (count) of b(i).

MATLAB: 1D array combinations

This will generate a cell array of all combinations of all possible lengths:

C = cell(size(A));
for k = 1:numel(C)
    C{k} = nchoosek(A,k);
end

contained inside this cell array:

>> C{:}
ans =
   1
   2
   3
   4
   5
ans =
   1   2
   1   3
   1   4
   1   5
   2   3
   2   4
   2   5
   3   4
   3   5
   4   5
ans =
   1   2   3
   1   2   4
   1   2   5
   1   3   4
   1   3   5
   1   4   5
   2   3   4
   2   3   5
   2   4   5
   3   4   5
ans =
   1   2   3   4
   1   2   3   5
   1   2   4   5
   1   3   4   5
   2   3   4   5
ans =
   1   2   3   4   5

Without padding they will not fit into one numeric array, as they have different number of columns. To pad them try this:

C = cell(size(A));
for k = 1:numel(C)
    tmp = nchoosek(A,k);
    C{k} = [tmp,NaN(size(tmp,1),numel(A)-k)];
end
N = cell2mat(C);

which creates this numeric array:

>> N
N =
     1   NaN   NaN   NaN   NaN
     2   NaN   NaN   NaN   NaN
     3   NaN   NaN   NaN   NaN
     4   NaN   NaN   NaN   NaN
     5   NaN   NaN   NaN   NaN
     1     2   NaN   NaN   NaN
     1     3   NaN   NaN   NaN
     1     4   NaN   NaN   NaN
     1     5   NaN   NaN   NaN
     2     3   NaN   NaN   NaN
     2     4   NaN   NaN   NaN
     2     5   NaN   NaN   NaN
     3     4   NaN   NaN   NaN
     3     5   NaN   NaN   NaN
     4     5   NaN   NaN   NaN
     1     2     3   NaN   NaN
     1     2     4   NaN   NaN
     1     2     5   NaN   NaN
     1     3     4   NaN   NaN
     1     3     5   NaN   NaN
     1     4     5   NaN   NaN
     2     3     4   NaN   NaN
     2     3     5   NaN   NaN
     2     4     5   NaN   NaN
     3     4     5   NaN   NaN
     1     2     3     4   NaN
     1     2     3     5   NaN
     1     2     4     5   NaN
     1     3     4     5   NaN
     2     3     4     5   NaN
     1     2     3     4     5

Best Answer

Related Solutions

MATLAB: How to find ‘numbers’ of unique variable in matrix. How many quantity of variables.

MATLAB: 1D array combinations

Related Question