Find the equation of the circle which passes through the origin and cuts off intercepts $3$ and $4$ from the positive parts of the axes respectively.
My Attempt,
The circle cuts the axis of $X$ at $(3,0)$ and the axis of $Y$ at $(0,4)$. Let $r$ be the radius of the circle. Since the circle passes through the origin,
$$r=\sqrt {h^2+k^2}$$,
Where, $(h,k)$ are the co ordinates of the centre of the circle.
Best Answer
Let the equation of the circle be $$x^2+y^2+2gx+2fy+c=0$$
Now it passes through $(0,0);(3,0);(0,4)$
We have three unknowns with there conditions, right?