Find the equation of the circle touching each axis and passing through $(2,1)$
My Attempt:
Since the circle touches both axes, the x-coordinate of the center = y-coordinate of the center = radius. If $h$, $k$ and $r$ are the x-coordinate, y-coordinate and radius then
$$h=k=r.$$
Best Answer
The equation of your circle is then $(x-r)^2+(y-r)^2=r^2$. Plug in $x=2,y=1$ and solve for $r$.