TikZ: Get colour from an array and use it for drawing

Question

Using the arrayjob package, I am able to extract strings from an array and, for example, get TikZ to print that text:

\documentclass{standalone}
\usepackage{tikz}
\usepackage{arrayjob}
\newarray\colours
\readarray{colours}{red&orange&yellow&green&blue&purple}

\begin{document}
    \begin{tikzpicture}
        \foreach \i in {1,2,5} {
            \draw (0,\i) node{\colours(\i)};
        }
    \end{tikzpicture}
\end{document}

However, I want to colour lines with variable colours in the same way. Naively, I try the following code, which does not work:

\documentclass{standalone}
\usepackage{tikz}
\usepackage{arrayjob}
\newarray\colours
\readarray{colours}{red&orange&yellow&green&blue&purple}

\begin{document}
    \begin{tikzpicture}
        \foreach \i in {1,2,5} {
            \draw[\colours(\i)] (0,\i)--++(1,0);
        }
    \end{tikzpicture}
\end{document}

This is a toy example to illustrate what I want. There are obvious ways to do this in this small example, but not my application. I want to extract the colour from an array by index and use that colour to colour the lines.

EDIT:
Thanks to SebGlav, I got something working. I'll leave that as an answer down below. There are three good solutions in the answers now, thank you everyone!

Answer 1

As suggested, using the array functionality of TikZ you can get:

\documentclass{standalone}
\usepackage{tikz}
%\usepackage{arrayjob}
%\newarray\colours
%\readarray{colours}{red&orange&yellow&green&blue&purple}
\def\mycolours{{"red","orange","yellow","green","blue","purple"}}

\begin{document}
    \begin{tikzpicture}
        \foreach \i [evaluate=\i as \usecolor using {\mycolours[\i]}]in {1,2,5} {
            \draw[color=\usecolor] (0,\i)--++(1,0);
        }
    \end{tikzpicture}
\end{document}