I am aware one can change the size of a single bracket to be slightly bigger than the object attached to it using \left\{<object>\right.
What I would really like to do though, is to manually set the exact height of a curly open bracket. (For example to \baselineskip
).
Does anyone know how exactly the height of a bracket as compared to the contained object is determined? (One could then use a strut of appropriate height to force the behaviour of the bracket).
Or perhaps there is a completely different method for achieving the effect I am looking for, one that does not make use of the \right
and \left
commands at all?
Best Answer
You can use
\bigl(
to get a different size, or (in size order\Bigl(
,\biggl(
,\Biggl(
the same commands withr
at the end produce right delimiters or just\big(
produces brackets of the same size as\bigl
and\bigr
, but with with mathord spacing.\big
is defined in plain TeX asso 8.5pt high. similar commands could be made for any size.