EDIT:
In order to make this question more beneficial for others, what I'm asking is how to simply vertically center the contents of a ''cell'', without having to modify all of the other parameters you have already established in the making of your table.
Is there any way to do this?
ORGINAL:
I'm trying to vertically center the contents of the following table:
\documentclass{article}
\usepackage[a4paper,margin=1in,landscape]{geometry}
\usepackage[utf8]{inputenc}
\usepackage[spanish]{babel}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{graphicx}
\usepackage{float}
\usepackage{array}
\begin{document}
\begin{center}
{\large\textbf{{Gu\'ia Probabilidad}}}
\noindent\makebox[\linewidth]{\rule{\textwidth}{1pt}}
\end{center}
\subsection*{Distribuciones Discretas:}
\begin{table}[H]
\center
\begin{tabular}{||c|c|c|c|c|c c@{}||}
\hline
Distribución & Funci\'on de masa de probabilidad & Par \'ametros & Media & Varianza & Funci\'on generadora de momentos&\\
\hline
\hline
\textit{Bernoulli} & $f(x) = p^x q^{1-x}I_{\{0,1\}}(x)$ & $0< p <1$ & $p$ & $p(1-p)$ & $(1-p) + pe^t$&\\[5ex]
\hline
\textit{Binomial} & $f(x) = \begin{pmatrix}n\\x\end{pmatrix}p^x(1-p)^{n-x}I_{0,1,\ldots,n}(x)$ & $0<p<1$ & $np$ & $np(1-p)$ & $(1-p + pe^t)^n$&\\[5ex]
\end{tabular}
\end{table}
\end{document}
I've already checked the answers of similar questions, but I just can't seem to find a simple answer. For example, the answers in this question distort the vertical alignment of my cells.
I think there just should be a really simple way to do this.
Thanks for the help.
PS for some reason I can't upload the image of my table…
Best Answer
like this?
note: in your mwe is defined seven columns, but used only six. therefore i deleted last (empty) columns. i use
makecell
package for adding vertical space to cells' contents.edit: it seems that you looking for this:
in above mwe i consider Mico comment below.