[Tex/LaTex] Variant of $\leq$ (less or equal)-symbol

Question

I am looking for a way to include a \leq that (to me) is less ugly. In the font I am using \leq simply produces a < with an underline, but in my handwriting the lower "arm" of the < would be parallel to the lower line.

To give you an impression of what I am aiming for here is a hack:

\newcommand{\fauxleq}{\mathrel{\rotatebox[origin=c]{25.5}{$\displaystyle\leqslant$}}}

which produces

obviously the lines are mismatched and also the angle is way to wide to look acceptable.

So, is anyone aware of a better solution (or a font that regularly draws \leq in the way I am looking way to "borrow" it from)?

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EDIT: @percusse : I don't know how to include an image in a comment. Is your point that \fauxleq is ugly? I know that, that's why I search for a better alternative

Answer 1

I find this a very bad idea, but the customer's always right.

\documentclass{article}
\usepackage{pict2e}

\DeclareRobustCommand{\fauxleq}{\mathrel{\mathpalette\dofauxleq\relax}}

\newcommand{\dofauxleq}[2]{%
    \sbox0{$\mathsurround=0pt #1\leq$}%
    \setlength{\unitlength}{\wd0}%
    \begin{picture}(1,0.7)
    \roundcap\roundjoin
    \put(0.1,0){\line(1,0){0.8}}
    \polyline(0.9,0.2)(0.1,0.2)(0.9,0.7)
    \end{picture}%
}

\begin{document}

$A\fauxleq B_{\fauxleq}$

$A\leq B_{\leq}$

\end{document}