I've tried to put a rule long as the text in this way:
\rule{\textwidth}{0.4mm}
but I obtain a rule slightly smaller that the text width. How to obtain the same effect as \hrule?
[Tex/LaTex] the \rule equivalent to \hrule
indentationrules
Related Solutions
Based on @lockstep answer, I've created a wrapper environment which allows the minipage width to be specified as an argument.
%adds minipage to inside of algorithms
\newlength{\tightalgowidth}
\newlength{\tightalgoremainder}
% uncomment to use centered floating algorithms
\newenvironment{tightalgo}[2][]
{
\setlength{\tightalgowidth}{#2}
\setlength{\tightalgoremainder}{\linewidth-\tightalgowidth}
\begin{algorithm}[#1] }
{ \end{algorithm} }
\makeatletter
\patchcmd{\@algocf@start}{%
\begin{lrbox}{\algocf@algobox}%
}{%
\rule{0.5\tightalgoremainder}{\z@}%
\begin{lrbox}{\algocf@algobox}%
\begin{minipage}{\tightalgowidth}%
}{}{}
\patchcmd{\@algocf@finish}{%
\end{lrbox}%
}{%
\end{minipage}%
\end{lrbox}%
}{}{}
\makeatother
Use it like this
\begin{tightalgo}[ht]{0.5\linewidth}
\caption{NaiveSelect}\label{algo:naive-option}
Some alg step \;
Some other \;
\end{tightalgo}
For this result
You have to \moveright a box with a rule in it, but also to watch out against page breaks before the rule
\def\beginrecipe{
\par
\begingroup
\leftskip=\baselineskip
\multiply\leftskip by 2
\rightskip=\leftskip
\parindent=-\baselineskip
\parfillskip=0pt plus 1fil
\nobreak
\reciperule
}
\def\endrecipe{
\par\nobreak
\reciperule
\endgroup
}
\def\reciperule{
\nointerlineskip
\vskip0.5em
\moveright\baselineskip\vbox{
\advance\hsize-3\baselineskip
\hrule width \hsize
}
\nointerlineskip
\nobreak
\vskip0.5em
}
\beginrecipe
{\bf Blonde roux}
2 tbsp of butter.
2 tbsp of flour.
Melt the butter in a pan and add the flour.
Cook the flour without browning for 2 minutes, stirring with a whisk.
Cook the flour without browning for 2 minutes, stirring with a whisk.
\endrecipe
\bye
Best Answer
According to p. 221 of the TeXbook, the height of
\hruleis 0.4pt.