line-breakingmatrices
To make things easy, I have put up a pic here, I do not understand how I can reduce the size of the long entries in the matrix (the diagonal entries primarily) and also introduce line breaks so as to print a matrix similar to this one here.
Any help will be much appreciated.
Thanks and regards,
Florian
My answer only deals with the third matrix in your MWE, as it's the most challenging one to typeset in a visually appealing way. Like some of the other answers and comments have already noted, it's not necessary (as well as, I'd say, rather ugly) to make the column heights equal to the column widths. My answer below therefore adds only a small amount of whitespace between the rows (via the \extrarowheight parameter). The column widths, however, are all forced to be the same. Furthermore, it would seem (at least for the case at hand) that it's preferable to left-align rather than to center the cells' contents.
\documentclass{article}
\usepackage{amsmath}
\usepackage[margin=1in]{geometry}
\newlength{\mycolwidth}
\settowidth{\mycolwidth}{$A_{n-1,-1}^{n-2}$} % widest entry
\usepackage{array}
\newcolumntype{Z}{>{$}p{\mycolwidth}<{$}}
\begin{document}
First, the plain (bmatrix) solution:
\begin{equation}
\begin{bmatrix}
A_{-n,0}^{-n} & A_{-n+1,-1}^{-n} & 0 & \cdots & \cdots & \cdots & \cdots & 0 \\
A_{-n,1}^{-n+1} & A_{-n+1,0}^{-n+1} & A_{-n+2,-1}^{-n+1} & \ddots & && & \vdots \\
0 & A_{-n+1,1}^{-n+2} & A_{-n+2,0}^{-n+2} & A_{-n+3,-1}^{-n+2} & \ddots & & & \vdots \\
\vdots & \ddots & \ddots & \ddots & \ddots & \ddots & & \vdots \\
\vdots & & \ddots & \ddots & \ddots & \ddots & \ddots& \vdots\\
\vdots & & & \ddots & A_{n-3,1}^{n-2} & A_{n-2,0}^{n-2} & A_{n-1,-1}^{n-2} & 0\\
\vdots & && & \ddots & A_{n-2,1}^{n-1} & A_{n-1,0}^{n-1} & A_{n,-1}^{n-1}\\
0 & \cdots & \cdots & \cdots & \cdots & 0 & A_{n-1,1}^{n} & A_{n,0}^{n} \\
\end{bmatrix}
\end{equation}
Second, a solution that forces all columnwidths to be the
same, left-aligns the cells' contents, and increases the
distances between rows:
\setlength{\extrarowheight}{1.5\baselineskip}
\begin{equation}
\left[ \begin{array}{*{8}{Z}}
A_{-n,0}^{-n} & A_{-n+1,-1}^{-n} & 0 & \cdots & \cdots & \cdots & \cdots & 0 \\
A_{-n,1}^{-n+1} & A_{-n+1,0}^{-n+1} & A_{-n+2,-1}^{-n+1} & \ddots & && & \vdots \\
0 & A_{-n+1,1}^{-n+2} & A_{-n+2,0}^{-n+2} & A_{-n+3,-1}^{-n+2} & \ddots & & & \vdots \\
\vdots & \ddots & \ddots & \ddots & \ddots & \ddots & & \vdots \\
\vdots & & \ddots & \ddots & \ddots & \ddots & \ddots& \vdots\\
\vdots & & & \ddots & A_{n-3,1}^{n-2} & A_{n-2,0}^{n-2} & A_{n-1,-1}^{n-2} & 0\\
\vdots & && & \ddots & A_{n-2,1}^{n-1} & A_{n-1,0}^{n-1} & A_{n,-1}^{n-1}\\
0 & \cdots & \cdots & \cdots & \cdots & 0 & A_{n-1,1}^{n} & A_{n,0}^{n} \\[5ex]
\end{array} \right]
\end{equation}
\end{document}
I cannot see the sense of all those zeros. However, use:
\noindent
\resizebox{\linewidth}{!}{\arraycolsep=2pt%
$X_1 = \left(
\begin{array}{@{}*6r}
1.059200000000000 & -1.059200000000000 & 0 & 0 & 0 & 0 \\
-1.059200000000000 & 1.059200000000000 & 0 & 0 & 0 & 0 \\
0 & 0 & 1.059200000000000 & -1.059200000000000 & 0 & 0 \\
0 & 0 & -1.059200000000000 & 1.059200000000000 & 0 & 0 \\
0 & 0& 0.364800000000000 & -1.364800000000000 & 0.694400000000000 & 0.305600000000000 \\
0 & 0 & -1.364800000000000 & 0.364800000000000 & 0.305600000000000 & 0.694400000000000 \\
\end{array}
\right)
$}
Best Answer
Environment
smallmatrixof packageamsmathprovides a matrix with smaller fonts and manual line breaks, e.g.: