macros
I have one command named \commandone, which outputs
test.
I created it using \newcommand\commandone{test}
I want to have a second command \commandtwo{}, which takes an integer input and call the first command \commandone repeatedly according to the input integer. So if \commandtwo{3}, the output will become "
testtesttest
You need \edef; the step \edef\X{\Alph{ctr}} is not needed.
\documentclass{article}
\newcounter{ctr}
\loop
\stepcounter{ctr}
\expandafter\edef\csname S\Alph{ctr}\endcsname{\noexpand\mathcal{\Alph{ctr}}}
\ifnum\thectr<26
\repeat
\begin{document}
$\SA$
\end{document}
An \edef free solution:
\documentclass{article}
\count255=`A \advance\count255 -1
\loop
\advance\count255 1
\begingroup\uccode`A=\count255
\uppercase{\endgroup
\expandafter\def\csname SA\endcsname{\mathcal{A}}%
}
\ifnum\count255<`Z
\repeat
\begin{document}
$\SA$
\end{document}
An expl3 solution:
\documentclass{article}
\usepackage{xparse}
\ExplSyntaxOn
\int_step_inline:nnnn { 1 } { 1 } { 26 }
{
\cs_new:cpx { S\int_to_Alph:n {#1} } { \exp_not:N \mathcal{ \int_to_Alph:n { #1 } } }
}
\ExplSyntaxOff
\begin{document}
$\SA$ $\SZ$
\end{document}
the use of \tl:use:N appears wrong but from the desired output I guess you want
which is obtained from
\documentclass{article}
% only needed for old latex \usepackage{expl3}
\ExplSyntaxOn
\NewDocumentCommand{\mycommand}{m}{
%
\tl_set:Nx \l_firstIndex_tl { \use_i:nn #1 }
\tl_set:Nx \l_secondIndex_tl { \use_ii:nn #1 }
%
\str_case:VnF \l_secondIndex_tl
{
{1} { one }
{2} { two }
{3} { three }
}
{No~case~found.}
}
\ExplSyntaxOff
\begin{document}
Test the code:
\par \mycommand{21} \% Not OK - expected output: "one"
\par \mycommand{26} \% OK - expected output: "No case found."
\par \mycommand{2a} \% OK - expected output: "No case found."
\end{document}
(answer updated to use \str_case:VnF in place of exp_args:NV\tl_case:NnF whch is cleaner and avoids using an N rgument with a character token (which works but is a mild abuse as it's supposed to be a command name token))
Best Answer