Tables – Typesetting a Prisoner’s Dilemma Table in LaTeX

Question

I am going to create a table, which should look like The Prisoner's Dilemma, but I can't create it.

It should look like this:

My preamble look like this:

\documentclass[a4paper,12pt,oneside]{article}
\usepackage[english]{babel}
\usepackage{tikz}
\usepackage{pgf}
\usetikzlibrary{shapes,arrows,positioning,calc} 
\usepackage{tabu}
\usepackage{hyperref}
\usepackage{longtable}
\usepackage{array}
\usepackage{siunitx,multirow,tabularx,booktabs}
\renewcommand{\arraystretch}{1.5}
\def\mathbi#1{\textbf{\em #1}}
\newcommand{\transp}{^{\mathsf{T}}}

\begin{document}

\begin{table}[h]
     \begin{center}
      \caption{The Prisoner’s Dilemma}
     \begin{tabular}{c | c | c |}
     &Factor1&Defect\\\hline%
     Factor2&5&4\\
     Defect&2&2\\\hline
     \end{tabular}
     \end{center}
     \end{table}

\end{document}

And the table look like this:

Can someone tell me how to make the first table with AND without the extra box? The cells should be the same size.

Answer 1

With TikZ it is far simpler:

The code:

\documentclass[tikz,border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{calc,matrix}

\begin{document}

\begin{tikzpicture}[element/.style={minimum width=1.75cm,minimum height=0.85cm}]
\matrix (m) [matrix of nodes,nodes={element},column sep=-\pgflinewidth, row sep=-\pgflinewidth,]{
         & Factor 1  & Factor 2  \\
Factor 1 & |[draw]|5 & |[draw]|4 \\
Factor 2 & |[draw]|2 & |[draw]|2 \\    };

\node[draw,element, anchor=west,label={above:\textbf{Name 3}}] at ($(m-2-3)!0.5!(m-3-3)+(1.25,0)$) {5}; % setting the node midway to cell 4 and cell 2 with a horizontal shift of 1.25cm

\node[above=0.25cm] at ($(m-1-2)!0.5!(m-1-3)$){\textbf{Name 1}};
\node[rotate=90] at ($(m-2-1)!0.5!(m-3-1)+(-1.25,0)$){\textbf{Name 2}};
\end{tikzpicture}

\end{document}

The version within article

\documentclass[11pt,a4paper]{article}
\usepackage{tikz}
\usetikzlibrary{calc,matrix}

\usepackage{lipsum}

\begin{document}
\lipsum[1]

\begin{table}[h]
\centering
\caption{bla bla bla}
\label{bla}
\begin{tikzpicture}[element/.style={minimum width=1.75cm,minimum height=0.85cm}]
\matrix (m) [matrix of nodes,nodes={element},column sep=-\pgflinewidth, row sep=-\pgflinewidth,]{
         & Factor 1  & Factor 2  \\
Factor 1 & |[draw]|5 & |[draw]|4 \\
Factor 2 & |[draw]|2 & |[draw]|2 \\    };

\node[draw,element, anchor=west,label={above:\textbf{Name 3}}] at ($(m-2-3)!0.5!(m-3-3)+(1.25,0)$) {5}; % setting the node midway to cell 4 and cell 2 with a horizontal shift of 1.25cm

\node[above=0.25cm] at ($(m-1-2)!0.5!(m-1-3)$){\textbf{Name 1}};
\node[rotate=90] at ($(m-2-1)!0.5!(m-3-1)+(-1.25,0)$){\textbf{Name 2}};
\end{tikzpicture}
\end{table}

\lipsum[2]

\end{document}

The result:

Explanation

A TikZ matrix is simply a node and as every node some anchors become available: incidentally this helps a lot in positioning other elements in the picture.

The first step is to give a name to the matrix: it is done through the syntax \matrix (m) where m is the name. Using the option matrix of nodes then also each cell has a name in the form <matrix name>-<row>-<column>.

Since we have a name we can access anchors as <matrix name>.<anchor>. But we have to know where these anchors are located. For debugging purposes we can add this code right after the previous \matrix definition:

% debugging purposes
\draw[red](m.south west)rectangle(m.north east);

\foreach \anchor/\placement in
    {north/above,  south/below, east/right, west/left,
     north west/above, north east/above,
     south west/below, south east/below}
     \draw[shift=(m.\anchor)] plot[mark=x] coordinates{(0,0)} node[\placement=0.15cm]{\scriptsize\texttt{(m.\anchor)}};

Now the table looks like:

In the picture there are two notes: they are added with

% Where to put the notes according to what we learnt about matrices
\node[below=0.5cm] at (m.south west) {Note};
\node[below=0.5cm, align=center,text width=5cm] at (m.south) {Another Note which is supposed to be longer};