bracesbracketsequations
I'm using \overbrace to explain a part of an equation, like this:
\begin{align}
a\left[\frac{d\cos y}{e} + \overbrace{\frac{b\sin x}{c}}^{\text{second bit}}\right]
\end{align}
But the overbrace increases the height of the brackets unnecessarily:
Really, what I'd like is for the height of the brackets to be unrelated to the overbrace, like this:
Is this possible?
You can use \vphantom to adjust the size so that max is used. The macro below has 4 parameters:
0.425\textwidth.\parbox\parboxHere is what it looks like with a curly brace: \RelatedText{\}}{\lipsum[2]}{\lipsum[3]}
\documentclass[12pt]{memoir}
\usepackage{lipsum}
\newcommand{\RelatedText}[4][0.425\textwidth]{%
\begin{math}%
\left.%
\parbox{#1}{#3}\vphantom{\parbox{#1}{#4}}%
\right#2%
\parbox{#1}{#4}\vphantom{\parbox{#1}{#3}}%
\end{math}
}%
\begin{document}
\RelatedText{)}{\lipsum[2]}{\lipsum[3]}% Use a round )
\RelatedText{\}}{\lipsum[2]}{\lipsum[3]}% Use a curly }
\RelatedText{]}{\lipsum[2]}{\lipsum[3]}% Use a square ]
\end{document}
You don't need \left and \right; your input has several mistakes, by the way: for instance \split{equation} means nothing (and it will produce errors). Also “mean” should be treated as an operator. I don't think the parentheses () around the set are useful.
With split you can choose the alignment point; here's a possibility:
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{split}
X_{t} = \operatorname{mean}(\{\,
&\lvert Y_{t-4} - Z_{t-4}\rvert,\dots,\\
&\lvert Y_{t+4} - Z_{t+4}\rvert\,\})
\end{split}
\end{equation}
\end{document}
Best Answer