equationsmath-modematricessetspace
I am having some difficulty getting this to display properly.
\begin{equation}
{\bf H} = -{\bf \mu} \cdot {\bf B} = - \gamma B_o {\bf S}_z = -\frac{\gamma B_o\hbar}{2}
\begin{bmatrix} 1&0\\0&-1 \end{bmatrix}.
\end{equation}
Which appears as,
I would like the matrix height to be consistant with the rest of the equation.
I \smashed the over and undersets, so that the matrix would not know of them. However, I had to compensate with a leading rule to accound for the vertical space that was smashed (the three 4ex expressions in the \rule can be changed in size to increase or decrease the gap above/below the expression).
Struts had to be added outside the over- and under-sets so as to get the parens to set to the right vertical size and also inside the over- and under-sets to get the braces to stand off from the expression appropriately.
\documentclass{article}
\usepackage{amsmath}
\usepackage{xfrac}
\usepackage{lipsum}
\begin{document}
\lipsum[3]
\begin{gather*}
\rule[\dimexpr-4ex-\ht\strutbox]{0pt}{\dimexpr4ex+4ex+\baselineskip}
H_{8kl}=
\begin{pmatrix}
\strut\smash{\overbrace{\strut\sfrac{1}{2} (A+B)\otimes E + \sfrac{1}{2} (A-B)\otimes G}^{K}} &
\strut\smash{\overbrace{\strut\sfrac{1}{2} (A+B)\otimes F + \sfrac{1}{2} (A-B)\otimes H}^{L}}\\
\strut\smash{\underbrace{\strut\sfrac{1}{2} (C+D)\otimes E + \sfrac{1}{2} (C-D)\otimes G}_{M}} &
\strut\smash{\underbrace{\strut\sfrac{1}{2} (C+D)\otimes F + \sfrac{1}{2} (C-D)\otimes H}_{M}}
\end{pmatrix}
\end{gather*}
\lipsum[4]
\end{document}
Since you want a cheat sheet, I'd recommend the extract package. With a slightly different MWE:
\documentclass{article}
\usepackage[
active,
header=false,
copydocumentclass=true,
generate=\jobname-Cheatsheet,
extract-env={equation},
extract-cmdline={synopsis},
]{extract} % http://ctan.org/pkg/extract
\begin{extract*}
% Items executed in both the main and extracted document
% (extract manual, section 5.1)
\usepackage{amsmath}
\end{extract*}
\begin{extract}
% Items executed only in extracted document
\def\synopsis#1{#1}
\end{extract}
\def\synopsis#1{}
\begin{document}
First Euler observed that
\synopsis{Euler's equation tying together the five fundamental constants of mathematics}%
\begin{equation}
1 + e^{i \Pi} = 0.
\end{equation}
Then, Gauss discovered the normal distribution:
\synopsis{Normal distribution}%
\begin{equation}
P(x) = \frac{1}{{\sigma \sqrt {2\pi } }}e^{{{ - \left( {x - \mu } \right)^2 } \mathord{\left/ {\vphantom {{ - \left( {x - \mu } \right)^2 } {2\sigma ^2 }}} \right. \kern-\nulldelimiterspace} {2\sigma ^2 }}}
\end{equation}
Finally, Einstein proclaimed:
\synopsis{Equivalence of mass and energy}%
\begin{equation}
E = m C^2
\end{equation}
\end{document}
you get an original document of:
and an extracted document of:
\documentclass{article}
% Items executed in both the main and extracted document
% (extract manual, section 5.1)
\usepackage{amsmath}
% Items executed only in extracted document
\def\synopsis#1{#1}
\begin{document}
\synopsis{Euler's equation tying together the five fundamental constants of mathematics}%
\begin{equation}
1 + e^{i \Pi} = 0.
\end{equation}
\synopsis{Normal distribution}%
\begin{equation}
P(x) = \frac{1}{{\sigma \sqrt {2\pi } }}e^{{{ - \left( {x - \mu } \right)^2 } \mathord{\left/ {\vphantom {{ - \left( {x - \mu } \right)^2 } {2\sigma ^2 }}} \right. \kern-\nulldelimiterspace} {2\sigma ^2 }}}
\end{equation}
\synopsis{Equivalence of mass and energy}%
\begin{equation}
E = m C^2
\end{equation}
\end{document}
and:
This also works with your original \caption command.
Best Answer