[Tex/LaTex] Make graph where nodes and connecting edges are circles

circlesdiagramsgraphsnodestikz-pgf

I am struggling to figure out how to make a graph that connects 12 circular nodes in a circle. I have the code:

\begin{tikzpicture}
\graph [nodes={draw, circle}, clockwise, radius=3in, nodes, n=12] {
subgraph C_n [name=outer]
};
\end{tikzpicture}

which gives me this:

but I would like the edges connecting them to be curved so that it resembles a circle rather than a dodecahedron. Since this issue is similar to anti-clockwise pathed curve for connecting nodes I tried replicating that code, but with 12 nodes instead of four, which gave me a square. The only advantage to this method was that I was able to start the nodes at 0 rather than 1, as I would like to do in my final product.

\begin{tikzpicture}[->,>=stealth',shorten >=1pt,auto,node distance=3cm,    thick,main node/.style={circle,draw,font=\sffamily\Large\bfseries}]
\node[main node] (1) {0};
\node[main node] (2) [below right of=1] {1};
\node[main node] (3) [below right of=2] {2};
\node[main node] (4) [below right of=3] {3};
\node[main node] (5) [below left of=4] {4};
\node[main node] (6) [below left of=5] {5};
\node[main node] (7) [below left of=6] {6};
\node[main node] (8) [above left of=7] {7};
\node[main node] (9) [above left of=8] {8};
\node[main node] (10) [above left of=9] {9};
\node[main node] (11) [above right of=10] {t};
\node[main node] (12) [above right of=11] {e};

\path[every node/.style={font=\sffamily\small}]
(1) edge [bend right] node[right] {} (2)
(2) edge [bend right] node[right] {} (3)
(3) edge [bend right] node[right] {} (4)
(4) edge [bend right] node[right] {} (5);
(5) edge [bend right] node[right] {} (6)
(6) edge [bend right] node[right] {} (7)
(7) edge [bend right] node[right] {} (8)
(8) edge [bend right] node[right] {} (9);
(9) edge [bend right] node[right] {} (10)
(10) edge [bend right] node[right] {} (11)
(11) edge [bend right] node[right] {} (12)
(12) edge [bend right] node[right] {} (1);
\end{tikzpicture}

Is there a way to make both the nodes and edges circular?

Best Answer

What about:

\documentclass[tikz]{standalone}
\usetikzlibrary{graphs, graphs.standard}

\begin{document}

\begin{tikzpicture}
\graph [nodes={draw, circle}, clockwise, radius=3in, nodes, n=12, edge={bend left=12}] {
subgraph C_n [name=outer]
};
\end{tikzpicture}

\end{document}

Edit: after again reading your question, I found that you want to start with 0. So, possibly this is an acceptable solution:

\documentclass[tikz]{standalone}
\usetikzlibrary{graphs, graphs.standard}

\begin{document}

\begin{tikzpicture}
\graph [nodes={draw, circle, minimum width=.25in, inner sep=0pt}, clockwise, radius=1in, nodes, n=12, V={0,...,11}, ->, edge={bend left=10,>=stealth}] {
subgraph C_n [name=outer]
};
\end{tikzpicture}

\end{document}

Remarks

Concerning your questions

You can use the mark inside property on your path, where the first argument is the segment of the path where the mark will be placed, e.g. \draw[mark inside=0.7] (0,0) -- (1,1); will set the mark at 70% of the line.
I introduced an additional node in between the three ones called (helper).

Implementation

\documentclass[tikz]{standalone}
\usetikzlibrary{petri,decorations.markings}
\tikzset{
    >=latex,
    node distance = 2cm,
    every place/.style = {minimum size = 6mm},
    mark inside/.style = {
        postaction = {
            decorate,
            decoration={
                markings,
                mark=at position #1 with {\draw[-] (0,-0.1) -- (0,0.1);}
            }
        }
    }
}
\begin{document}
\begin{tikzpicture}
    % Places
    \node[place,tokens=1] (p0)                                           {};
    \node[coordinate]     (start)  [node distance=0.5cm,left of=p0]      {};
    \node[place,tokens=1] (p1)     [right of=p0]                         {};
    \node[place]          (p2)     [above right of=p1]                   {};
    \node[place]          (p3)     [below right of=p1]                   {};
    \node[coordinate]     (helper) [below right of=p2]                   {};
    \node[place]          (p4)     [node distance=0.7cm,right of=helper] {};
    \node[coordinate]     (end)    [node distance=0.5cm,right of=p4]     {};
    % Connections
    \draw (start)   edge[->]                               (p0.west);
    \draw (p0.east) edge[>->]                              (p1.west);
    \draw (p1.east) edge[>->,mark inside=0.5,out=0,in=180] (p2.west);
    \draw (p1.east) edge[>->,mark inside=0.5,out=0,in=180] (p3.west);
    \draw (p2.east) edge[>-,out=0,in=180]                  (helper);
    \draw (p3.east) edge[>-,out=0,in=180]                  (helper);
    \draw (helper)  edge[mark inside=0,->]                 (p4.west);
    \draw (p4.east) edge[>-]                               (end);
\end{tikzpicture}
\end{document}

Output

[Tex/LaTex] Draw edge on arc

you say:

drawing an arc alone does not draw arrows and does not end at the "borders" of the nodes, but at there center

(*their center, b.t.w.)

but it is not completely true; you can try with a workaround with arc. For example:

\draw [right, ->] (0.3,8) arc [radius=4, start angle=90, end angle= 0];

will draw an arrow from V1 to almost V2.

Playing around with the radius and the location of the nodes you can draw your circle (with arrows, see the -> above)

EDIT:

to avoid playing around with the starting location you can use node anchors:

\draw [->] (V1.east) arc [radius=4, start angle=90, end angle= 0];

Best Answer

Related Solutions

[Tex/LaTex] TikZ edge between multiple source nodes and single target node

Remarks

Implementation

Output

[Tex/LaTex] Draw edge on arc

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