[Tex/LaTex] indent somelines with the usepackage algorithm2e

algorithm2e

I want to indent all lines after this line function(w,v with the usepackage algorithm2e. How can I get that to work?

text

\documentclass{article}
\usepackage{german,t1enc}
%pseudocode.
\usepackage[linesnumbered,ruled,vlined]{algorithm2e} 
\renewcommand{\baselinestretch}{1.5}
\begin{document}
\begin{algorithm}[H]

function(w,v) \\
  formed the  Suffix-Array $s$ von $w$; \\
  compare Suffix $S[i]$ with Suffix $S[j]$ and find the LCP then store the
  result in array x;

\caption{}
\end{algorithm}
\end{document}

Best Answer

I am assuming you wish to have a subroutine in your algorithm and that is why you wish to indent. you should looks at this thread

as to your code, without much work you could simply indent with \qquad

\documentclass{article}
\usepackage{german,t1enc}
%pseudocode.
\usepackage[linesnumbered,ruled,vlined]{algorithm2e} 
\renewcommand{\baselinestretch}{1.5}
\begin{document}
\begin{algorithm}[H]

function(w,v) \\
  \qquad formed the  Suffix-Array $s$ von $w$; \\
  \qquad compare Suffix $S[i]$ with Suffix $S[j]$ and find the LCP then store the
  \qquad result in array x;

\caption{}
\end{algorithm}
\end{document}

Related Solutions

[Tex/LaTex] Problems with algorithm2e and \If

You seem to be mixing your syntax between what is provided by algorithm2e and that of algorithmicx. The latter uses a \For{..} ... \EndFor and \If{..} ... \EndIf construction while the former uses \For{..}{...} and \If{..}{...} construction together with a \; line-terminating macro.

Here's an algorithm2e implementation:

enter image description here

\documentclass{article}
\usepackage{amsmath,algorithm2e}
\newcommand{\var}{\texttt}
\begin{document}

\begin{algorithm}
  \ForAll {Partition p}{%
    $\var{skip1} = 0$\;
    \ForAll {\text{edges} $i = (a,b)$}{%
      $\var{skip2} = 0$\;
      \ForAll {\text{bucket in $p$}}{%
        $j = 0$ % conta i caratteri
        \ForAll{\text{\var{chr} in bucket}}{%
          \eIf{\text{$\var{chr} = a$ or $\var{chr} = b$}}{
            $\var{other2find} = set(set((a,b,)) - set((chr,)))$\; % give the missing element to find
            $\var{skip1} = 1$\;
            \ForAll {\text{other char $k$}}{%
              \If{$\var{other2find} = k$}{%
                $\var{unstableNumber} = \var{unstableNumber} + 1$\;
                $\var{skip2} = 1$\;
                break\; % smette di cercare nei caratteri del bucket
              }
              break\;
            }
          }{
            $j = j + 1$\;
          }
        }
      }
    }
    \If{\var{skip2}}{%
      break\; % non serve controllare tutti gli archi per sapere che una partizione non e' stabile
    }
    \If{not \var{skip2}}{%
      stablePartition.append(p)\;
      $\var{skip2} = 0$\;
    }
  }
\end{algorithm}

\end{document}

Note that it would be advisable to define a macro for your variable definitions (like skip1, skip2, chr, ...) that you can use throughout your algorithms. You may want to do the same for function calls, or use \call. See the algorithm2e documentation for many more options/details.

[Tex/LaTex] Write the else if block with algorithm2e

To combine such conditions, write each as a separate component using \uIf and \uElseIf (and \uElse, if needed):

\documentclass{article}

\usepackage[linesnumbered,ruled,vlined]{algorithm2e} 

\begin{document}

\begin{algorithm}[H]
  \uIf{if condition}{
    something if \;
  }
  \uElseIf{elseif condition}{
    something elseif \;
  }
  \Else{
    something else \;
  }
\caption{An algorithm}
\end{algorithm}

\end{document}

Best Answer

Related Solutions

[Tex/LaTex] Problems with algorithm2e and \If

[Tex/LaTex] Write the else if block with algorithm2e

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