Original
The remainder provided by polynom.sty
is NOT complete (as shown in the following figure).
My Objective
When I was in senior high school, my teacher made the diagram like below. 🙂
Thus the final step must show the TOTAL remainder and mark it with L-shaped curve.
NOTE
I am sorry. The previous post I forgot to put back -1/4
in the original position. It have made you confused. Now there is no mistake anymore. 🙂
Minimal Code
\documentclass{article}
\usepackage{polynom,array}
\usepackage[table]{xcolor}
\makeatletter
\def\pld@ArrangeResult#1{%
\ifx\pld@remainder\@empty
\@tempcnta\pld@maxcol\relax
\pld@InsertItems@do\pld@lastline
{\pld@firsttrue\pld@PLD{\pld@R{0}{1}}}%
\fi
\ifnum\pld@currstage>\z@
\pld@Extend\pld@allines{\pld@lastline\cr}%
\else
\pld@InsertFake\pld@lastline
\fi
\pld@iftopresult
\def\pld@lastline{\pld@PrintPoly\pld@divisor%
%====================================================================================
\quad\smash{{\color{red}\rule[-6pt]{\arrayrulewidth}{17pt}}}\kern-\arrayrulewidth&}%
%====================================================================================
\else
\let\pld@lastline\@empty
\ifx B\pld@style\else
\def\pld@lastline{\pld@leftdelim\strut\pld@rightxdelim&}%
\fi
\fi
\expandafter\pld@AR@col\expandafter\pld@PLD
\expandafter\pld@lastline#1+\relax+%
\pld@SplitQuotient
\pld@iftopresult
\let\pld@currentline\@empty
\expandafter\pld@AR@col\expandafter\pld@PLD
\expandafter\pld@currentline
\pld@quotient+\relax+%
\expandafter\pld@AR@col\expandafter\pld@XPLD
\expandafter\pld@currentline
\pld@shadow+\relax+%
\edef\pld@subline{%
\noexpand\cline{\tw@-\pld@maxcol}%
\noalign{\vskip\jot}}%
\pld@Extend\pld@currentline{\expandafter\cr\pld@subline}%
\else
\@tempcnta-\@tempcnta
\advance\@tempcnta\pld@maxcol\relax \advance\@tempcnta\@ne
\edef\pld@span{\the\@tempcnta}%
\ifx B\pld@style
\pld@AddTo\pld@lastline{%
&\multispan\pld@span${}=%
\pld@PrintPolyWithDelims\pld@divisor
\expandafter\pld@IfSum\expandafter{\pld@divisor}{}{\cdot}%
\expandafter\pld@IfSum\expandafter{\pld@quotient}\pld@true
\pld@false
\pld@if \pld@leftdelim
\pld@PrintPolyShadow
\pld@rightdelim
\else \pld@PrintPolyShadow \fi
\pld@firstfalse
\expandafter\pld@PrintRemain\expandafter{\pld@remainder}$}%
\else
\pld@AddTo\pld@lastline{%
&\multispan\pld@span$\pld@leftxdelim\strut\pld@rightdelim
\pld@div
\pld@PrintPolyWithDelims\pld@divisor=
\pld@PrintPolyShadow
\ifx\pld@remainder\@empty\else
+{}%
\setbox\z@=\hbox{$\displaystyle
\frac{\let\strut\@empty\pld@firsttrue \expandafter
\pld@PrintRemain\expandafter{\pld@remainder}}%
{\let\strut\@empty\pld@PrintPoly\pld@divisor}$}%
\dp\z@=\z@\box\z@
\fi
$}%
\fi
\fi
\expandafter\pld@AR@\pld@allines\relax}
\makeatother
\arrayrulecolor{red}
\arrayrulewidth=0.8pt
\def\strut{\rule[-6pt]{0pt}{12pt}}
\begin{document}
\polylongdiv[style=A]{\frac{3}{7}x^9+x^2-\frac{1}{4}}{\frac{9}{5}x^4-1}
\vspace{1cm}
\polylongdiv[style=A]{x^4-1}{x^2-1}
\end{document}
Best Answer
The following code should work; I've included a few test cases. To keep the code shorter, I didn't include your changes to the style of the output (red color, and bar between dividend and divisor instead of parenthesis). My changes and additions to
polynom
are marked with!!!
.