How would I make a 16-gon only showing the vertices? I want to number the vertices and then connect certain ones with lines. I literally just started using TikZ in LaTeX so help would be appreciated.
[Tex/LaTex] How to make a 16-gon
tikz-pgf
Related Solutions
Something like this?
\documentclass[tikz,border=3mm]{standalone}
\usepackage{tikz-feynman}
\begin{document}
\begin{tikzpicture}
\begin{feynman}
\vertex (li);
\vertex [below=2cm of li] (hi);
\vertex [right=of li] (a);
\path (a) ++ (20:2) node[vertex] (lf);
\vertex [below right=of a] (b);
\vertex [right=of b] (hf1);
\vertex [blob, right=of hi] (c) {};
\path (c.-10) ++ (00:2) node[vertex] (hf2);
\path (c.-40-|hf2.center) node[vertex] (hf3);
\diagram* {
(li) -- [fermion] (a) -- [fermion] (lf),
(hi) -- [fermion] (c) -- [fermion] (b),
(a) -- [photon] (b) -- [fermion] (hf1),
(c.-10) -- [fermion] (hf2),
(c.-40) -- [fermion] (hf3)
};
\end{feynman}
\end{tikzpicture}
\end{document}
You may want to nudge the positions of the arrows a bit.
\documentclass[tikz,border=3mm]{standalone}
\usepackage{tikz-feynman}
\begin{document}
\begin{tikzpicture}
\begin{feynman}
\vertex (li);
\vertex [below=2cm of li] (hi);
\vertex [right=of li] (a);
\path (a) ++ (20:2) node[vertex] (lf);
\vertex [below right=of a] (b);
\vertex [right=of b] (hf1);
\vertex [blob, right=of hi] (c) {};
\path (c.-5) ++ (00:2) node[vertex] (hf2);
\path (c.-40-|hf2.center) node[vertex] (hf3);
\diagram* {
(li) -- [fermion] (a) -- [fermion] (lf),
(hi) -- [fermion] (c) -- [fermion] (b),
(a) -- [photon] (b) -- [fermion] (hf1),
(c.-5) -- [fermion] (hf2),
(c.-40) -- [with arrow=0.52] (hf3)
};
\end{feynman}
\end{tikzpicture}
\end{document}
Source of inspirations: tikzfeynman.keys.code.tex.
Best Answer
An n-gon showing only the vertices is a circle. So it won't make too much difference but TikZ has a geometric shapes library. To show only the vertices remove the
drawoption from the first node.