With tikz
and little bit of cheating (i.e., using inkscape2tikz
):
\documentclass{article}
\usepackage{tikz}
\newcommand{\Lira}{%
\begin{tikzpicture}[x=0.08em, y=0.08em, xscale=0.03, yscale=-0.03, inner sep=0pt, outer sep=0pt]
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(82.3075,45.7791) .. controls (82.3075,67.2598) and (82.3075,79.2984) ..
(82.3075,81.8950) -- (167.2860,51.0903) .. controls (167.2860,59.3521) and
(167.2860,66.7877) .. (167.2860,73.3971) -- (82.3075,104.2018) .. controls
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(208.0048,171.3584) and (202.4576,192.9571) .. (191.3632,213.2575) .. controls
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(54.3355,50.7362) .. controls (54.3355,33.5045) and (54.3355,19.6955) ..
(54.3355,9.3092) -- cycle;
\end{tikzpicture}}
\begin{document}
This will cost you 10\Lira.
\end{document}
Best Answer
This assumes that the arc of the P is half the height of the letter.