rulestables
I need to draw a double line after the first row in a table, but when using \hline twice, this interrupts the vertical lines:
\documentclass{article}
\begin{document}
\begin{tabular}{|c|c|c|}
\hline
1 & 2 & 3 \\ \hline \hline
4 & 5 & 6 \\ \hline
7 & 8 & 9 \\ \hline
\end{tabular}
\end{document}
produces:
This is without using any additional packages. How can I change this is such a ways that the vertical lines are not interrupted?
I believe your problem is that you didn't put enough empty cells for the following lines. A multirow will allow content to occupy space, but doesn't actually create the cells that are under it. I rewrote your code aligning everything to illustrate that.
\begin{tabular}{l r | l || r r}
Vzorka & Výskyty & Algoritmus & Porovnania & Prístupy \\ \hline
\multirow{5}{*}{Gabriel} & \multirow{5}{*}{8} & NAIVE BINARY & 158 & 44 \\
& & NAIVE BINARY_LCP & 174 & 92 \\
& & NAIVE INTERPOLATION & 168 & 78 \\
& & LESS NAIVE BINARY & 98 & 26 \\
& & LESS NAIVE BINARY_LCP & 124 & 58 \\ \hline
\end{tabular}
This is tricky. What you have is actually a 3-dimensional table that you want to represent as a 2-dimensional image on the page. There are 3 input values and 3³ = 27 output values.
I think what you want here is Occam's Razor...
For example:
You could even play around with removing the vertical rules entirely and replacing them with vertical whitespace:
Maybe even rewrite the zeros as dashes, if the data still happens to make sense that way...
Note: I'm not sure that the latter two forms are actually clearer, even though they are less complex for the eyes to process. The reason is that, as mentioned earlier, this is inherently a 3-dimensional table with 27 values. The final two forms — which use horizontal rules only — muddy the dimensionality as they lead the eye to scan left-to-right. Compare and contrast this with the second form, in which the double-stroked rules serve to separate the three 3x3 grids from the labels above and to the left.
As much as I dislike vertical rules and double-stroked rules in general, I think the second form might actually be the clearest of the five shown here. I'd be curious to hear your thoughts.
In any event, below is the LaTeX source for the samples above.
\documentclass{article}
\usepackage{booktabs}
\usepackage{nicefrac}
\newcommand{\half}{\nicefrac{1}{2}}
\begin{document}
\begin{tabular}{|r||ccccc|ccccc|ccccc|}
\hline
ContainsPrize &&& A &&&&& B &&&&& C &&\\
\hline
MyChoice && A & B & C &&& A & B & C &&& A & B & C &\\
\hline\hline
openA && 0 & 0 & 0 &&& 0 & \half & 1 &&& 0 & 1 & \half &\\
openB && \half & 0 & 1 &&& 0 & 0 & 0 &&& 1 & 0 & \half &\\
openC && \half & 1 & 0 &&& 1 & \half & 0 &&& 0 & 0 & 0 &\\
\hline
\end{tabular}
\vskip 3em
\begin{tabular}{r||ccccc|ccccc|ccccc}
ContainsPrize &&& A &&&&& B &&&&& C &&\\
\hline
MyChoice && A & B & C &&& A & B & C &&& A & B & C &\\
\hline\hline
openA && 0 & 0 & 0 &&& 0 & \half & 1 &&& 0 & 1 & \half &\\
openB && \half & 0 & 1 &&& 0 & 0 & 0 &&& 1 & 0 & \half &\\
openC && \half & 1 & 0 &&& 1 & \half & 0 &&& 0 & 0 & 0 &\\
\end{tabular}
\vskip 3em
\begin{tabular}{r|ccccc|ccccc|ccccc}
ContainsPrize &&& A &&&&& B &&&&& C &&\\
\hline
MyChoice && A & B & C &&& A & B & C &&& A & B & C &\\
\hline
openA && 0 & 0 & 0 &&& 0 & \half & 1 &&& 0 & 1 & \half &\\
openB && \half & 0 & 1 &&& 0 & 0 & 0 &&& 1 & 0 & \half &\\
openC && \half & 1 & 0 &&& 1 & \half & 0 &&& 0 & 0 & 0 &\\
\end{tabular}
\vskip 4em
\setlength{\tabcolsep}{.5em}
\begin{tabular}{r c ccc c ccc c ccc}
\toprule
ContainsPrize &~~~~~~&~ & A & ~&~~~& ~ & B & ~&~~~& ~ & C & ~\\
\midrule
MyChoice && A & B & C && A & B & C && A & B & C\\
\toprule
openA && 0 & 0 & 0 && 0 & \half & 1 && 0 & 1 & \half\\
openB && \half & 0 & 1 && 0 & 0 & 0 && 1 & 0 & \half\\
openC && \half & 1 & 0 && 1 & \half & 0 && 0 & 0 & 0\\
\bottomrule
\end{tabular}
\vskip 4em
\setlength{\tabcolsep}{.5em}
\begin{tabular}{r c ccc c ccc c ccc}
\toprule
ContainsPrize &~~~~~~&~ & A & ~&~~~& ~ & B & ~&~~~& ~ & C & ~\\
\midrule
MyChoice && A & B & C && A & B & C && A & B & C\\
\toprule
openA && -- & -- & -- && -- & \half & 1 && -- & 1 & \half\\
openB && \half & -- & 1 && -- & -- & -- && 1 & -- & \half\\
openC && \half & 1 & -- && 1 & \half & -- && -- & -- & --\\
\bottomrule
\end{tabular}
\end{document}
Best Answer