[Tex/LaTex] Horizontal shift in tabular environment

horizontal alignmenttables

My question is the most efficient way to do in tabular environment the last row of the table in the image below. Numbers are shifted horizontally by an half column.
thankyou!
enter image description here

Best Answer

Here's a solution that uses the S column type (provided by the siunitx package) to assure that the numeric-data columns are all equally wide. I also suggesting using the \midrule macro (from the booktabs package), instead of \hline, to get well-spaced horizontal rules.

enter image description here

\documentclass{article}
\usepackage{booktabs} % for \midrule macro
\usepackage{siunitx}  % for 'S' column type
\begin{document}

\begin{table}
\centering
\sisetup{table-format=-1.0}
\setlength\arraycolsep{2pt} % default value: 5pt
$\begin{array}{l @{\quad} *{19}{S} }
K & 0 && 1 && 2 && 3 && 4 && 5 && 6 && 7 && 8 && 9\\
\midrule
y_K & 2 && 3 && 5 && 8 && 9 && 9 && 8 && 7 && 7 && 6\\
\midrule
\Delta y_K && 1 && 2 && 3 && 1 && 0 && -1 && -1 && 0 && -1\\
\end{array}$
\end{table}
\end{document}

Related Solutions

[Tex/LaTex] Table: Can I shift a column by half the height of a row

\documentclass[a4paper]{article}
\usepackage{collcell,array}
\newcommand{\shiftdown}[1]{\smash{\raisebox{-.5\normalbaselineskip}{#1}}}
\newcolumntype{C}{>{\collectcell\shiftdown}c<{\endcollectcell}}
\begin{document}
\begin{tabular}{cC}
A & \multicolumn{1}{c}{ratio}\\
\hline
3 &2\\
6 &3\\
18
\end{tabular}
\end{document}

The \multicolumn{1}{c}{...} is necessary to avoid applying the shift also to the heading.

[Tex/LaTex] Brace spanning multiple rows in a table and horizontal alignment

For this kind of stuff I find it best to use \tikzmark:

enter image description here

I was not sure where you wanted the brace, so the brace below might not be where you want it. But do the table as you normally would and get the text in the correct spot. Include a \tikzmark{<nameA>} and \tikzmark{<nameB>} to mark the location of the two end points of the brace. Then provide the name of those two marks to \DrawVerticalBrace to do the actual drawing.

Notes:

This does require two runs. First one to determine the locations, and the second to do the drawing.
The \tikzmark is from Adding a large brace next to a body of text.

Code:

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{calc,decorations.pathreplacing}

\newcommand{\tikzmark}[1]{%
  \tikz[overlay,remember picture,baseline] \node [anchor=base] (#1) {};}


\newcommand{\DrawVerticalBrace}[3][]{%
    % [<draw options>]{<mark>}{<mark>}
    \begin{tikzpicture}[overlay,remember picture]
        \draw[decorate,decoration={brace,amplitude=1ex}, #1] 
            ($(#3)+(0.0em,-0.5ex)$) to
            ($(#2)+(0.0em,+1.7ex)$);%
    \end{tikzpicture}%
}

\begin{document}
\begin{tabular}{ l c r }
   $T=0$ & $T=1$ & $T=2$ \\
   $-1$ & \multicolumn{2}{l}{$
   \begin{array}{l l}
     \tikzmark{top}0 & R\\
     \tikzmark{bot}1 & 0
   \end{array} $}
\end{tabular}
\DrawVerticalBrace[red, thick]{top}{bot}%
\end{document}