[Tex/LaTex] \frac command: height of the numerator vs height of denominator

fractions

I have the following code:

\begin{equation}
 \underline{W}^1_{\,q,\rho} =  \left\lceil
 \frac{\sum\limits_{v \in
Q, v \neq q}\underline{C}_{\,v} + \sum\limits_{i=\rho+1}^{|\Omega^{(U)}_q|}p_i+
\sum\limits_{i \in U \backslash \Omega^{(U)}_q}p_i%
+\underline{TT}_{\,q, \rho} }{m-1}
 \right\rceil\,,
\end{equation}

that is rendered as:

enter image description here

As you may see, the numerator height is the same as the denominator. I don't need all this waste of empty space.
How can I avoid this situation?

Best Answer

Not a real answer to your question, see below.

\documentclass{article}
\usepackage{amsmath}

\begin{document}

\begin{equation}
\underline{W}^1_{\,q,\rho} =
\biggl\lceil \frac{1}{m-1}
  \biggl(\,
  \sum_{v \in Q, v \neq q}\underline{C}_{\,v} +
  \sum_{i=\rho+1}^{|\Omega^{(U)}_q|}p_i +
  \sum_{i \in U \setminus \Omega^{(U)}_q}p_i +
  \underline{TT}_{\,q, \rho}
  \biggr)
\biggr\rceil,
\end{equation}
\end{document}

enter image description here

Note that you don't need \limits when in a display; also \backslash should be \setminus. Note also that \left and \right would give an inferior result, because they would cover also the big upper limit, which is not necessary.

You can easily adapt this for a two column format:

\documentclass[twocolumn]{article}
\usepackage{amsmath}

\begin{document}

\begin{multline}
\underline{W}^1_{\,q,\rho} =
\biggl\lceil \frac{1}{m-1}
  \biggl(\,
  \sum_{v \in Q, v \neq q}\underline{C}_{\,v} + {}\\
  \sum_{i=\rho+1}^{|\Omega^{(U)}_q|}p_i +
  \sum_{i \in U \setminus \Omega^{(U)}_q}p_i +
  \underline{TT}_{\,q, \rho}
  \biggr)
\biggr\rceil,
\end{multline}
\end{document}

enter image description here

Why does that horrible result appear? Because the main fraction line is set on the “formula axis” and fences are set to cover the material and be centered on the axis.