[Tex/LaTex] Figure in columns in itemize

beamercolumnsitemize

I`m trying to make an itemized list, where only one of the items has an image to the right.
I tried this

\documentclass{beamer}
\usetheme{Dresden}
\begin{document}
\begin{frame}{Problem}
  \begin{itemize}
     \item 
     \begin{columns}
        \column{.7\linewidth}
        Here I want some text with an image to the right, all in the same item
        \column{.3\linewidth}
        \rule{.2\linewidth}{.2\linewidth}
     \end{columns}
     \item Some more text here that is long enough to continue bellow the image
 \end{itemize}
\end{frame}
\end{document}

But this is what I get instead

columns not inside item

Best Answer

You can use columns only for first item and close it before the second item.

Next code shows the solution. I has a little problem, columns don't use the complete \linewidth, first one is .65\linewidth and second .25\linewidth in order to align first and second item symbols. I think I've read something about this problem somewhere but I don't remember where now. If I find it I'll explain the solution.

\documentclass{beamer}
\usetheme{Dresden}

\begin{document}
    \begin{frame}{Solution}
        \begin{columns}
            \column{.65\linewidth}
            \begin{itemize}
                \item Here I want some text with an image to the right, all in the same item
            \end{itemize}
            \column{.25\linewidth}
            \rule{.2\linewidth}{.2\linewidth}
        \end{columns}
        \begin{itemize}
            \item Some more text here that is long enough to continue bellow the image
        \end{itemize}
    \end{frame}
\end{document}

enter image description here

Update

The reference I was looking for is provide more usable columns environment, an issue discussion in beamer's github place.

My conclusion is: it's safer to use totalwidth option to columns environment if you want to avoid problems with intercolumns spaces and margins. And more important: don't confuse \linewidth with \textwidth as I did in previous example.

\documentclass{beamer}
\usetheme{Dresden}

\begin{document}
    \begin{frame}{Solution}
        \begin{columns}[onlytextwidth] %<---
            \column{.7\textwidth} %<---
            \begin{itemize}
                \item Here I want some text with an image to the right, all in the same item
            \end{itemize}
            \column{.3\textwidth} %<---
            \rule{.2\linewidth}{.2\linewidth}
        \end{columns}
        \begin{itemize}
            \item Some more text here that is long enough to continue bellow the image
        \end{itemize}
    \end{frame}
\end{document}

Related Solutions

[Tex/LaTex] aligning a multiline formula with the bullet of itemize

I would definitely go the second way with $\displaystyle: I find that it looks strange to have something centered after a bullet. To get the vertical alignment correct, just add [t] after \begin{aligned}, where "t" means "top". (See also the top of page 8 of the User's guide for the amsmath Package.)

[Tex/LaTex] How to top align itemize in two columns in beamer

Use some \vphantoms in the itemize to the left so items on both environments have the same height:

\documentclass{beamer}
\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage{graphicx}
\usepackage[caption=false]{subfig}
\usepackage{braket}
\usepackage{geometry}
\usepackage{empheq}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage[backend=biber,url=false,doi=false,isbn=false,firstinits=true]{biblatex}

\begin{document}

\begin{frame}{Angular Spectrum Method}{Free Space Propagation}
    A constant index medium such as free space is: 
    \begin{itemize}
        \item isotropic \pause $\Rightarrow$ diagonal permittivity, permeability tensors \pause
        \item spatially uniform \pause $\Rightarrow$ relative permittivity and permeability are constants equal to 1 \pause
        \item Source free \pause $\Rightarrow$ $\mathbf{J} = 0$, $\rho = 0$
    \end{itemize}
    \pause
    \begin{columns}[T]
    \begin{column}[T]{.5\textwidth}
        \vspace{0pt}
        \begin{itemize}
            \item<7-> Polarisation Independent!\vphantom{$ \dfrac{ \partial^2 \mathbf{E} }{ \partial t }$}
            \item<8-> Modes are plane waves\vphantom{$A_\mathbf{k} e^{ \mathbf{k} \cdot \mathbf{r} }$}
        \end{itemize}
    \end{column}
    \hfill
    \begin{column}[T]{.5\textwidth}
        \begin{itemize}
            \item<7-> $ \nabla^2 \mathbf{E} - \mu_0 \mu_r \epsilon_0 \epsilon_r \dfrac{ \partial^2 \mathbf{E} }{ \partial t } =  0 $
            \item<8-> $ E_i = \sum_\mathbf{k} A_\mathbf{k} e^{ \mathbf{k} \cdot \mathbf{r} } $
            \item<8-> $ \left( \dfrac{ 2 \pi n }{ \lambda } \right)^2 = k^2 = k_x^2 + k_y^2 + k_z^2 $
        \end{itemize}
    \end{column}
    \end{columns}
\end{frame}

\end{document}