Why do I get a false integral symbol when I do \bm{\int(2x}? I've just loaded the package bm in a usual way, and I'm not using any other different font in the preamble.
[Tex/LaTex] False bold integral symbol
boldmath-modesymbols
Related Solutions
You can us bm to access the bold + from the font used for \boldmath (which in the standard setup is the font used for \bfseries in text.
\documentclass{article}
\usepackage{bm}
\begin{document}
\showoutput
$1 + 2 \bm{+} 3$
\end{document}
Define a new math font from a new font family besides the default cmex, for instance, mdbch and euex. Refer to arevmath.sty.
\documentclass{article}
%define a new command for \rm font of int
\DeclareSymbolFont{rmlargesymbols}{OMX}{mdbch}{m}{n}
% or \DeclareSymbolFont{rmlargesymbols}{U}{euex}{m}{n}
\DeclareMathSymbol{\rmintop}{\mathop}{rmlargesymbols}{82}
\newcommand{\rmint}{\rmintop\nolimits}
\begin{document}
$\rmint_a^b$
\[\rmint_a^b \]
\end{document}
Best Answer
The range of symbols available depends on the fonts used, and the classic Computer Modern collection doesn't have a bold version of the symbol extension font used for integral signs.
Assuming you don't want to change font setup globally there are a couple of choices. Use an extra set of
{..}so\bmsees this as a complex expression and just uses\boldmathinternally. This will make the other symbols bold but leave the integral sign from the standard font. or you could modify the poor man's bold to offset the symbols by a smaller amount so the gaps don't show. The original used an arbitrary value of.4muhere I use.2mu.