equations
how can I get two equations one below the other, listed on the right side
\begin{equation}
LCS(X_{n},Y_{m-1})\\ enumerate
LCS(X_{n-1},Y_{m})
\end{equation}
I try with this:
\begin{align}
LCS(X_{n},Y_{m-1})\\
LCS(X_{n-1},Y_{m})
\end{align}
but
I do not want to have two enumerates, I just want a enumerate for both
Does this help?
\documentclass{article}
\makeatletter
\newdimen\mymathindent
\newenvironment{bulletequation}%
{\@beginparpenalty\predisplaypenalty
\@endparpenalty\postdisplaypenalty
\refstepcounter{equation}%
\trivlist \item[]\leavevmode
\hb@xt@\linewidth\bgroup $\m@th% $
\displaystyle
\hskip\mymathindent}%
{$\hfil % $
\displaywidth\linewidth\hbox{\@eqnnum}%
\egroup
\endtrivlist}
\makeatother
\begin{document}
\begin{itemize}
\item \begin{bulletequation} 1+2=3\end{bulletequation}
\end{itemize}
\end{document}
Here is another approach, with some braces added to "combine" the separate equation sets. Of course, these can be removed if needed. Each equation set is aligned along the binary relations in an rcl (right-center-left) fashion with the appropriate spacing.
\documentclass{article}
\usepackage{amsmath}% http://ctan.org/pkg/amsmath
\begin{document}
\begin{align*}
\left.\begin{array}{r@{\mskip\thickmuskip}l}
\nabla f(x) -\mu X^{-1} e + A(x) \lambda - z &= 0, \\
c(x) &= 0, \\
-\mu X^{-1} e + z &= 0, \\
x &> 0 \\
z &> 0
\end{array} \right\}
\quad \implies \quad
\left\{\begin{array}{r@{\mskip\thickmuskip}l}
\nabla f(x) + A(x) \lambda - 2z &= 0, \\
c(x) &= 0, \\
-\mu X^{-1} e + z &= 0, \\
x &> 0 \\
z &> 0
\end{array}\right.
\end{align*}
\end{document}
Best Answer
Just to propose you multiple options
gives