Next time, please remember to provide a Minimum (non-)Working Example.
In this case, just draw it as an arc:
\documentclass[tikz, border=10pt]{standalone}
\begin{document}
\begin{tikzpicture}
\draw (0,0) arc (-180:-270:8 and 4);
\end{tikzpicture}
\end{document}
One can compute the correct angle using pgfmath and atan2.
\documentclass{article}
\usepackage{tkz-euclide}
\usetikzlibrary{intersections}
\usetkzobj{all}
\begin{document}
\begin{tikzpicture}[line cap=round,line join=round]
\tkzDefPoint(0,0){A}
\tkzDefPoint(3,0){B}
\tkzDefPoint(-4,-2){C}
\draw[dashed,thin,name path=elip] (A) ellipse (3cm and 1cm);
\draw[draw=none,name path=AC] (A)--(C);
\draw[name intersections={of=elip and AC, by={D}}];
\tkzDrawPoints[fill=black](A,B,C,D)
\tkzDrawSegments(A,B A,D D,C)
\tkzLabelPoints(A,B,C,D)
\tkzFindAngle (B,A,D) \tkzGetAngle{an} \FPround\an\an{0}
\pgfmathsetmacro{\ann}{atan2(sin(\an),cos(\an)/3)}% compute compensated angle
\draw (B) arc (0:\ann:3cm and 1cm);
\draw (0,2) node{$\widehat{BAD}=\an^\circ$};
\end{tikzpicture}
\end{document}
Best Answer
Of course you can draw half an ellipse with
arc
. The syntax isarc(<start angle>:<end angle>:<radius X> and <radius Y>)
, here are two examples.