[Tex/LaTex] Creating a Payoff Matrix Using LaTeX Tabular Environment

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I'm trying to use my limited knowledge of LaTeX to create a payoff matrix by hand. Here's my first try:

\begin{tabular}{cc|c|c|}
              &                 & Player $Y$      & \\
              &                 & $A$               & $B$ \\
\hline
Player $X$  & $A$               & $(x,y)$           & $(x,y)$ \\
\hline          
              & $B$           & $(x,y)$         & $(x,y)$ \\
\hline
\end{tabular}

However, what I've written isn't great, because

The lines extend too far, instead of simply creating a box enclosing the payoffs
How to center "Player X" and "Player Y" over the box?
There's also a mysterious "missing $" error.

Are there any tips I'm missing that would fix these issues and make this into a great-looking payoff matrix? Thanks for your help!

Best Answer

Please post complete minimal examples rather than code fragments. They make it much easier to help.

Maybe something like this?

I don't know why you would want 'Player Y' centred over any box, so I've assumed you don't really mean it.

\documentclass{article}
\usepackage{multirow,array}
\begin{document}
  \begin{table}
    \setlength{\extrarowheight}{2pt}
    \begin{tabular}{cc|c|c|}
      & \multicolumn{1}{c}{} & \multicolumn{2}{c}{Player $Y$}\\
      & \multicolumn{1}{c}{} & \multicolumn{1}{c}{$A$}  & \multicolumn{1}{c}{$B$} \\\cline{3-4}
      \multirow{2}*{Player $X$}  & $A$ & $(x,y)$ & $(x,y)$ \\\cline{3-4}
      & $B$ & $(x,y)$ & $(x,y)$ \\\cline{3-4}
    \end{tabular}
  \end{table}
\end{document}

payoff

Or possibly

  \begin{table}
    \setlength{\extrarowheight}{2pt}
    \begin{tabular}{*{4}{c|}}
      \multicolumn{2}{c}{} & \multicolumn{2}{c}{Player $Y$}\\\cline{3-4}
      \multicolumn{1}{c}{} &  & $A$  & $B$ \\\cline{2-4}
      \multirow{2}*{Player $X$}  & $A$ & $(x,y)$ & $(x,y)$ \\\cline{2-4}
      & $B$ & $(x,y)$ & $(x,y)$ \\\cline{2-4}
    \end{tabular}
  \end{table}

alternative

Related Solutions

[Tex/LaTex] strategy / payoff matrix

Here is a solution using tabular (a tikz solution follows).

\begin{tabular}{ccccc}
&&\multicolumn{2}{c}{Payoff Matrix}\\
&&\multicolumn{2}{c}{Firm B}\\
&&Low Price&High Price\\
\cline{3-4}
\raisebox{-0.25cm}{\rotatebox{90}{A}}&\multicolumn{1}{p{1cm}}{Low Price}&
\multicolumn{1}{|p{1.5cm}}{\hfill $10$\newline $10$\hfill}&
\multicolumn{1}{|p{1.5cm}|}{\hfill $5$\newline $25$\hfill}\\
\cline{3-4}
\raisebox{-0.25cm}{\rotatebox{90}{Firm}}&\multicolumn{1}{p{1cm}}{Low Price}&
\multicolumn{1}{|p{1.5cm}}{\hfill $5$\newline $25$\hfill}&
\multicolumn{1}{|p{1.5cm}|}{\hfill $20$\newline $20$\hfill}\\\cline{3-4}
\end{tabular}

Here is the result

enter image description here

Here is a tikz solution: (note: I fixed an alignment problem in the code, but I did not update the picture)

\documentclass{minimal}

\usepackage{tikz}
\usetikzlibrary{calc}
\usetikzlibrary{matrix}
\usetikzlibrary{positioning}

\begin{document}

\begin{tikzpicture}

\matrix[matrix of math nodes,every odd row/.style={align=right},every even row/.style={align=left},every node/.style={text width=1.5cm},row sep=0.2cm,column sep=0.2cm] (m) {
10&5\\
10&25\\
5&20\\
25&20\\
};
\draw (m.north east) rectangle (m.south west);
\draw (m.north) -- (m.south);
\draw (m.east) -- (m.west);

\coordinate (a) at ($(m.north west)!0.25!(m.north east)$);
\coordinate (b) at ($(m.north west)!0.75!(m.north east)$);
\node[above=5pt of a,anchor=base] {Low Price};
\node[above=5pt of b,anchor=base] {High Price};

\coordinate (c) at ($(m.north west)!0.25!(m.south west)$);
\coordinate (d) at ($(m.north west)!0.75!(m.south west)$);
\node[left=2pt of c,text width=1cm]  {Low Price};
\node[left=2pt of d,text width=1cm]  {High Price};

\node[above=18pt of m.north] (firm b) {Firm B};
\node[left=1.6cm of m.west,rotate=90,align=center,anchor=center] {Firm A};

\node[above=5pt of firm b]  {Payoff Matrix};
\end{tikzpicture}

\end{document}

The result is

enter image description here

[Tex/LaTex] Creating a transition probability matrix

You can use @{} specifications. Or see alternate approach that limits vertical line size.

\documentclass{article}
\usepackage{amsmath,blkarray}
\begin{document}
\[
\mathbf{P} = 
        \begin{blockarray}{c@{\hspace{1pt}}rrr@{\hspace{3pt}}}
         & 0   & 1   & 2 \\
        \begin{block}{r@{\hspace{1pt}}|@{\hspace{1pt}}
    |@{\hspace{1pt}}rrr@{\hspace{1pt}}|@{\hspace{1pt}}|}
        0 & 0.7 & 0.2 & 0.1 \\
        1 & 0.3 & 0.5 & 0.2 \\
        2 & 0   & 0   & 0   \\
        \end{block}
    \end{blockarray}
\]
\end{document}

ALTERNATE APPROACH:

This uses my tabstackengine and scalerel packages to achieve the OP's goal of limiting the vertical line height. I had to patch \Centerstack to omit the automatic \strut insertion.

\documentclass{article}
\usepackage{scalerel,tabstackengine,xpatch}
\setstacktabbedgap{1em}
\xpatchcmd\Centerstack{\strutlongstacks{T}}{}{}{}
\begin{document}
\[
\def\stackalignment{r}
\mathbf{P} = 
       \Centerstack{
        0  \\
        1  \\
        2    
        }\!
        \stackon{
        \stretchleftright{|\!|}{\tabbedCenterstack{
         0.7 & 0.2 & 0.1 \\
        0.3 & 0.5 & 0.2 \\
         0   & 0   & 0   
        }}{|\!|}}{\tabbedCenterstack{
        \protect\phantom{0.}0 & \protect\phantom{0.}1 & \protect\phantom{0.}2}
        \kern1pt}
\]
\end{document}

Best Answer

Related Solutions

[Tex/LaTex] strategy / payoff matrix

[Tex/LaTex] Creating a transition probability matrix

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