[Tex/LaTex] \begin{equation}: “Display math should end with $$” error

equationserrorsmath-mode

I'm pretty new to LaTeX, completely new actually, and there is one thing I can't quite understand.

I get the error "Display math should end with $$"
when writing an equation like this:

\begin{equation}

$R_{2}$=$\frac{U_{R_2}}{I_2}$=$\frac{2,95\, \mathrm{V}$}{$0,03*10^{-3}\, \mathrm{A}$} = 7,10\,\mathrm{k}\Omega \,.

\label{eq:Bsp_OhmsLaw}\end{equation}

I tried a lot of things, I also skimmed these forums. Nothing seemed to help 🙁

Thanks in advance!

Best Answer

In addition to removing the $ as cmhughes suggested, the blank lines in the equation environment confuse things. This may be why you added the dollar signs - with the blanks, LaTeX otherwise complains about missing $ symbols in the code.

Here's a working version:

\documentclass{article}

\begin{document}

\begin{equation}
  R_{2}=\frac{U_{R_2}}{I_2}=\frac{2,95\, \mathrm{V}}{0,03*10^{-3}\, \mathrm{A}} = 7,10\,\mathrm{k}\Omega \,.
  \label{eq:Bsp_OhmsLaw}
\end{equation}

\end{document}

equation

Related Solutions

[Tex/LaTex] “Display math should end with $$” error

It is an argument to listings not to \begin

                  %%%%%%%%%%%%
\begin{lstlisting}[mathescape]
$\infty$
\end{lstlisting}

The reason that you get that error is that TeX allows you to omit the braces around mandatory arguments, and if so takes the first token. so

\begin[mathescape]{lstlisting}$\infty$

\begin{[}mathescape]{lstlisting}$\infty$

Now \begin essentially does \begingroup\csname[\endcsname so this is

\begingroup\[mathescape]{lstlisting}$\infty$

so \[ starts display math and mathescape]{lstlisting} gets typeset as characters in display math mode, then the single $ is met but TeX wants a double $$ to end display math so issues a primitive error.

Basically error detection in a macro processing language is usually more by luck than design.

[Tex/LaTex] Display Math Should End With $$ error message

by default (it says in the comments in the class) solutions are not printed, you need the answers option. the error was because you can not have a paragraph break (blank line) in line math, I fixed some (not all:-) of the other issues such as obsolete font commands \bf and the option to the graphics package.

\documentclass[12pt,answers]{exam}

\usepackage{graphicx}

\usepackage{amsfonts,amssymb,amsmath,latexsym}

\pagestyle{empty}

\newcommand{\n}{\noindent}

\newcommand{\pp}{\parskip=0.25cm}

\newtheorem{tem}{\textsc{Theorem}}

\newcommand{\R}{\mathbb{R}}

\newcommand{\N}{\mathbb{N}}

\begin{document}

\title{\textbf{MA410.F13--Problem Set 1}}

\author{\textbf{Lisa Snay }}

\date{}

\maketitle

\begin{questions}\pp

\question[10] Prove that if $a\in\R$ and $a\not=0$, then $a^2>0$

\end{questions}

\begin{solution}

By Trichonomy, we know that $x > 0$, $x = 0$, or $x < 0$.

$x\not=0$ is given so we are left with two cases:

1--If $x>0$ then $x^2 = x\ x$

By order axiom six--if $0\leq x$ and $0\leq y$ then $0\leq x\ y$ so $x^2 > 0$.

2--If $x<0$ then 
\begin{align}x^2 &= -1 x -1 x\\ 
                  &= (-1)^2 x^2\\
              &= 1 x^2\\
             & = x^2 > 0
\end{align}, completing the proof.

\end{solution}

\end{document}

Best Answer

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[Tex/LaTex] “Display math should end with $$” error

[Tex/LaTex] Display Math Should End With $$ error message

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