color
I'm using xcolor.sty's nifty wheel function to define a color scheme based on a single base color. So, for example:
\definecolor{base}{HTML}{AADD96}
\colorlet{complement}{base>wheel,1,3}
makes base a pale green color, and complement a similarly pale blue (1/4 of the way round the color wheel).
Is there a way to similarly define colors by changing the saturation or brightness of an existing color?
A natural color is defined by its wavelength. If you want to print it you have to convert it into a color model which allows the mixing of base colors into the needed color. Such color models are very different and a blue in model A is often different to a blue in model B.
"blue" is a rgb color and "Blue" is defined as a cmyk color and handled by a different driver for your output. If you want to be sure, that you use the same driver, then specify one:
\documentclass[dvipsnames]{article}
\usepackage[rgb]{xcolor}
\begin{document}
{\color{Blue}\bf Blue} versus {\color{blue}\bf blue}.
\end{document}
instead of [rgb] you can also use [cmyk]
I guess this should receive downvotes instead of upvotes, but anyway:
\documentclass{article}
\begin{document}
% works only if you use PDFTeX or LuaTeX
% Don't do this at home, use \usepackage{xcolor} instead
\chardef\MyArticleWithColor=\pdfcolorstackinit page direct{0 g}
Roses are black
\pdfcolorstack\MyArticleWithColor push {0 0 1 rg}
Violets are blue
\pdfcolorstack\MyArticleWithColor pop
But I am not.
\end{document}
yields
Best Answer
You could use
\definecolorseries:will let you use
moresaturated!![1]for a somewhat more saturated colour,moresaturated!![2]for an even more saturated one, and so on. (But beware overflow: once the saturation reaches 1, it's reset to zero. Heremoresaturated!![4]is less saturated thanbase.)Obviously you can use the same trick to go down in saturation, or up or down in brightness.