alignhorizontal alignmentmath-mode
I was wondering if it is possible to take control of the exact position of the tab in an align environment.
Like so:
\begin{align}[2cm]
A &= x^3 + 14789\\
B &= f^6
\end{align}
Which should then place both '=' signs at exactly 2cm from the left margin. No matter how long the expressions before and after '=' are.
Does anyone know how to do something like that?
Your answer would have been self-evident have you provided an MWE. You must have something like the code below.
\documentclass[twocolumn,fleqn]{article} % The fleqn option left aligns equations
\usepackage[outer=0.2in,inner=0.1in]{geometry}
\usepackage{cases}
\setlength{\mathindent}{0cm}
\begin{document}
\begin{numcases}
{Opt\left(P, i, \ell \right)=min }
(1)\hspace{0.5 mm} Opt(P,i+1,\ell) + M(\ell,g)\label{eq:1}\hspace*{-10em} & \nonumber\\ % Put the command \nonumber before \\ and do not put \\ after the last line in order not to create a new equation line.
(2)\hspace{0.5 mm} \min_{g \in L(v_{i+1})}\{Opt(P,i+1,g) + M(\ell,g)\}\label{eq:2}\hspace*{-5em} & \nonumber
\end{numcases}
\end{document}
You want alignat:
\documentclass{article}
\usepackage{amsmath}
\begin{document}
You want
\begin{alignat}{2}
Z_i(f) &= R_i(f) && + i \cdot X_i(f) \label{eq:Zi} \\
Z_R(f) &= R && + i \cdot 0 \label{eq:ZR} \\
Z_L(f) &= 0 && + i \cdot \underbrace{ 2 \pi f L }_{X_L} \label{eq:ZL} \\
Z_C(f) &= 0 && - i \cdot \underbrace{ \frac{1}{2 \pi f \cdot C} }_{X_C} \label{eq:ZC}
\end{alignat}
\end{document}
Best Answer
In the following minimal example, the LHS ends at exactly 2cm from the left margin. The use of the
flalignenvironment (fromamsmath) with an additional alignment operator&pushes everything flush to the left margin, while a box of width 2cm leaves the LHS at the correct position.Only
Ais set in a 2cm block, sinceBis "short enough". Otherwise, you can set whatever in a 2cm box, regardless of the size.showframewas used to identify the text block border.