Does anybody know how I can get these symbols for a diagonal matrix in Latex?
Diagonal matrix in Latex
matrices
Related Solutions
Maybe this?
\documentclass{article}
\usepackage{amsmath,mathtools}
\DeclareMathOperator{\Mat}{Mat}
\newcommand{\diagentry}[1]{\mathmakebox[1.8em]{#1}}
\newcommand{\xddots}{%
\raise 4pt \hbox {.}
\mkern 6mu
\raise 1pt \hbox {.}
\mkern 6mu
\raise -2pt \hbox {.}
}
\begin{document}
\[
\Mat(u;\mathcal{B})=
\begin{pmatrix}
\diagentry{I_{n_+}}\\
&\diagentry{-I_{n_-}}\\
&&\diagentry{R_{\theta_1}}\\
&&&\diagentry{R_{\theta_2}}\\
&&&&\diagentry{\xddots}\\
&&&&&\diagentry{R_{\theta_r}}\\
&&&&&&\diagentry{0}\\
&&&&&&&\diagentry{0}\\
&&&&&&&&\diagentry{\xddots}\\
&&&&&&&&&\diagentry{0}\\
\end{pmatrix}
\]
\end{document}
Here's one option using the tikzmark library to define a command (using the optional argument one can control the vertical size):
The code:
\documentclass{article}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{tikzmark}
\newcounter{mydiagm}
\newcommand\DiagMat[2][1]{
\stepcounter{mydiagm}
\begin{bmatrix}
\tikzmark{start-\themydiagm}\rule{1cm}{0pt}\\[#1\normalbaselineskip]\hfill\tikzmark{end-\themydiagm}
\end{bmatrix}
\tikz[remember picture,overlay]
\draw ([yshift=1ex]pic cs:start-\themydiagm) -- node[fill=white,inner sep=2pt] {$#2$} (pic cs:end-\themydiagm);%
}
\begin{document}
\begin{equation*}
\DiagMat{c^{2}}\frac{\partial C_{l}}{\partial C_{T}}
\end{equation*}
\begin{equation*}
\DiagMat[2]{ce}
\begin{bmatrix}
a \\ b \\ c \\ d
\end{bmatrix}
\end{equation*}
\end{document}
The code needs two or three runs for the rule to reach its final position.
Best Answer
I am sure there must be a better way, but you can combine a rotated
rulewith the brackets and a fewhspaces and get kind of close. Note this won't scale vertically so don't try to put fractions (or something else tall) between the brackets. The expression with normal brackets is shown as well for comparison.