Circuitikz doesn’t draw transmission line with overlay option

circuitikztikz-pgf

Consider the following MWE.

\documentclass{article}

\usepackage{circuitikz}

\begin{document}

\begin{circuitikz}
  \draw (0,0) to [TL] (2,0);
\end{circuitikz}

\begin{circuitikz} [overlay]
  \draw (0,0) to [TL] (2,0);
\end{circuitikz}

\end{document}

For some reason the transmission line symbol is not drawn when using the overlay option.

Why is that and how can I get around it?

Best Answer

update:

should be fixed starting from 1.4.6, see https://github.com/circuitikz/circuitikz/issues/604

workaround

(but it breaks fill opacity, mind you; proper fix in the update above)

Puzzling. In the drawing of the TL legacy shape there is a transparency group (I do not remember why) that seems to confuse or badly interact with overlay. Removing it fixes the issue at hand, but I have to study it a bit more.

\documentclass{article}

\usepackage{circuitikz}
\makeatletter
\pgfcircdeclarebipolescaled{RF}
{}
{\ctikzvalof{bipoles/tline/height}}
{tline}
{\ctikzvalof{bipoles/tline/height}}
{\ctikzvalof{bipoles/tline/width}}
{
    \pgf@circ@res@step=.2\pgf@circ@res@right % half x axis
    % \begin{pgftransparencygroup}
        \pgf@circ@setlinewidth{bipoles}{\pgfstartlinewidth}
        \pgfpathmoveto{\pgfpoint{\pgf@circ@res@right-\pgf@circ@res@step}{\pgf@circ@res@up}}
        \pgfpathlineto{\pgfpoint{\pgf@circ@res@left+\pgf@circ@res@step}{\pgf@circ@res@up}}
        \pgfpatharc{-90}{90}{-\pgf@circ@res@step and -\pgf@circ@res@up}
        \pgfpathlineto{\pgfpoint{\pgf@circ@res@right-\pgf@circ@res@step}{\pgf@circ@res@down}}
        \pgf@circ@draworfill
        \pgfpathellipse{\pgfpoint{\pgf@circ@res@right-\pgf@circ@res@step}{0pt}}
        {\pgfpoint{\pgf@circ@res@step}{0pt}}{\pgfpoint{0pt}{-\pgf@circ@res@up}}
        \pgf@circ@draworfill
    % \end{pgftransparencygroup}
    \pgfsetlinewidth{\pgfstartlinewidth}
    \pgfpathmoveto{\pgfpoint{\pgf@circ@res@right-\pgf@circ@res@step}{0pt}}
    \pgfpathlineto{\pgfpoint{\pgf@circ@res@right}{0pt}}
    \pgfusepath{stroke}
}
\makeatother

\begin{document}

\begin{circuitikz}
  \draw (0,0) to [TL] (2,0) to[R] (4,0) to[generic] (6,0);
\end{circuitikz}

\begin{circuitikz} [overlay]
  \draw (0,0) to [TL] (2,0) to[R] (4,0) to[generic] (6,0);
\end{circuitikz}

\end{document}

Related Solutions

[Tex/LaTex] get an extra white page before the TikZ picture

use

\begin{landscape}
\resizebox{!}{0.95\textheight}{\input{erd.tikz.tex}}
\end{landscape}

The image is too big. The reason why it is placed on the following page.

[Tex/LaTex] Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawing

\draw (20,12) -- ++(2,0) -- ++(0,2) -- ++(-3,0) -- ++(45:3);

Use ++ before each new incremental coordinate to make it relative to the last one and put the pencil there.

Here's a complete example:

\documentclass{article}
\usepackage{tikz}
\begin{document}
\tikz\draw (20,12) -- ++(2,0) -- ++(0,2) -- ++(-3,0) -- ++(30:3) {[rounded corners=10pt]-- ++(5,0) -- ++(0,-6)} -- ++(-7,0) -- cycle;
\end{document}

Of course, combining this with the -| or |- path operators can simplify the code even further; the following two pieces of code produce the same result:

\tikz\draw (20,12) -- ++(2,0) -- ++(0,2) -- ++(3,0) -- ++(0,1) -- ++(1,0) -- ++(0,-3) -- ++(2,0);\par\bigskip

and

\tikz\draw (20,12) -| ++(2,2) -| ++(3,1) -- ++(1,0) |- ++(2,-3);

I don't think that defining commands in this case adds anything; in fact, I think it reduces the functionality of the existing syntax (which is already simple). The example demonstrates that you can use, for example, polar coordinates and modify (up to TikZ limitations) the path attributes midways; even if the current question doesn't require this, it's a good thing to have the possibility to do those kind of modification if they are required.