I am reading this post how \If{cond} \State{statement} \EndIf can be placed in the same line. Could you please someone suggest a way on how \If{cond} \State{statement} \Else \State{statement} \EndIf can be placed in the same line?
Algorithmic: Put If, Else and EndIf into the same line
algorithmic
Related Solutions
Yes there is: \ELSIF. This is one of the first examples taken from the algorithms bundle documentation (section 3.2 The if-then-else Statement, p 3):
\documentclass{article}
\usepackage{algorithmic}% http://ctan.org/pkg/algorithms
\begin{document}
\begin{algorithmic}
\IF{some condition is true}
\STATE do some processing
\ELSIF{some other condition is true}
\STATE do some different processing
\ELSIF{some even more bizarre condition is met}
\STATE do something else
\ELSE
\STATE do the default actions
\ENDIF
\end{algorithmic}
\end{document}
You can create your own "Intermediate IF" (or one-liner IF) statement using the following:
\documentclass{article}
\usepackage{algpseudocode}
\usepackage[Algorithmus]{algorithm}
\algnewcommand{\IIf}[1]{\State\algorithmicif\ #1\ \algorithmicthen}
\algnewcommand{\EndIIf}{\unskip\ \algorithmicend\ \algorithmicif}
\begin{document}
\begin{algorithm}
\caption{WHILE-Modulo}
\begin{algorithmic}[1]
\Require f($x_1,x_2$)
\State $x_z := 1$
\While{$x_z \not = 0$}
\If{$x_z = 1$} \IIf{$x_1 = 0$} $x_z = 10$ \EndIIf \EndIf
\IIf{$x_z = 2$} $x_3 := x_1 \dot{-}x_2$\EndIIf
\IIf{$x_z = 3$} $x_4 := x_2 \dot{-}x_1$\EndIIf
\If{$x_z = 4$} \IIf{$x_3 = 0$} $x_z = 7$\EndIIf \EndIf
\IIf{$x_z = 5$} $x_1 := x_3$\EndIIf
\IIf{$x_z = 6$} $x_z = 2$\EndIIf
\If{$x_z = 7$} \IIf{$x_4 = 0$} $x_z = 9$\EndIIf \EndIf
\IIf{$x_z = 8$} $x_z = 10$\EndIIf
\IIf{$x_z = 9$} $x_1 := x_1 \dot{-} x_2$\EndIIf
\IIf{$x_z = 10$} $x_z = 0$\EndIIf
\IIf{$x_z = 11$} $x_z = 0$\EndIIf
\EndWhile
\end{algorithmic}
\end{algorithm}
\end{document}
Best Answer
Add
then input
will generate output
Full example, based on Werner's answer https://tex.stackexchange.com/a/184228