As per what i learn that current(i) is rate at which charge flow through a cross section. Let assume we have 10 balls and it reaches another end while passing through some cross section, if 10 balls passes a cross section in 1 sec lets its current be i1 and if 10 balls passes a cross section in 0.1 sec lets its current be i2, so i2>i1
I know about the stopping potential, and how does we reach saturation current(If even an electron with negligible velocity is attracted toward collector plate, this max possible current is saturation current and its directly proportional to intensity)
And after saturation limit, if we further increase potential difference between collector and emitter, so electron arrives at greater speed (and i also know that number of photoelectrons wont increase or decrease as frequency, Intensity is kept constant)
Now the question :
If we assume 10 photoelectron emitted by plate (at saturation limit) to reaches collector. If we assume a cross section to be collector plate, so that 10 photoelectron cross it in 1 sec(just assume) if potential difference is say V1 to have photocurrent i1
If we increase potential difference to have V2 so now 10 photoelectron crosses collector plate in 0.1 sec(it has more Kinetic energy and it reaches earlier than in former case) to have photocurrent i2
As if V2 > V1 implies i2 > i1 after saturation.
What did i miss there, i know i am wrong but cant figure out where?
Best Answer
Imagine buses are running between two cities. Everyday 10 buses start from A and reach B. So 'bus current' is 10 bus per day.
Suppose speed of all buses is doubled. The time of journey will be reduced. 'Bus current' will remain same. Seperation between buses will increase.