Reason behind not using $H=V²/R$ for explaining the usage of high voltage in electric transmission lines

electric-currentelectrical-resistancepowervoltage

The answer to this question says that since there are multiple (3) potential difference across the entire circuit of power lines, the electricity is transmitted at high voltages. Also, they considered $$H=I^2Rt$$ and not $$H=\frac {V^2}{R}.$$
And a comment on the answer says that considering heat as a function of voltage here doesn't make sense as there are 3 voltages.

This made me think, is the voltage dropped across any resistance in the entire powerline circuit always the same?
Is it the "internal" resistance changing at the source itself? That's the only way I can think of where resistance across the transmission wires can be kept constant without an increase in voltage dropped across it, explaining how we can't use $H=\frac{V^2}{R}$ here for comparing heat loss.

Best Answer

H is the heat generated in the resistance of the line in a given time. $V^2$/R is the corresponding power. This considers only the current in one line, where the V is the voltage drop from one end of the line to the other. The line itself is a high voltage to minimize the current required to transmit a lot of power.