[Physics] Why sometimes we cant use force analysis must always use energy conservation or the work energy principle

energy-conservationhomework-and-exercisesnewtonian-mechanicswork

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According to the solution for this

It says work done by all the net forces on the block equals the potential energy of the spring at equilibrium and to calvulate work done it only considers the frictional force above the plane and the work done by gravity not work done by tension. Why tension does no work here ? Here the elongation of spring must be $0.1 m$ too.

But why is there no tension here won't the $1 kg$ block push the string and at first the spring will yield and then slowly it will oppose and tension should come.

Also why do we have to use energy analysis here why the answer comes wrong when I do by force analysis ie at equilibrium I equate force $kx$ to net force on block ie $mg sin(37°)$ – $f$ where $f$ is force of friction?

Best Answer

Even though the laws of motion allow us to deal with a whole range of problems, they fall short when it comes to variable forces. Remember that all the kinematic concepts or the dynamical problems you dealt with so far had constant acceleration.

The problem you've shown has a spring. And the spring force is not a constant force. It's a very good example of a variable force governed by the relationship:

$\vec{F}(x)=-k\vec{x}$

Where $\vec{x}$ is the displacement of the spring from it's intial position.

Since the displacements of the spring (a stretch or a compression) are in one dimension. The formula is often written as

$F(x)=-kx$.

Note that writing the force as $F(x)$ brings out the fact that it is not a constant. It is a function of the extension or compression $x$ of the spring.

I hope you can now understand why you're getting a wrong answer when you're blindly equating stuff. When you follow the incorrect approach, you assume that the force is constant.

Hence the concepts of work and energy often simplify problems.

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