I don't understand why the graph of force vs velocity^2 is a straight line in uniform circular motion. The equation for force in UCM is $F=m\frac{v^2}{r}$, I thought the graphs of such equations would be quadratic as the highest degree is 2. What am I missing to fully grasp the relationship between the two?
[Physics] Why is the relationship between centripetal force and velocity straight, in circular motion
centripetal-force
Best Answer
This is simpler than you think. You are quite correct that:
$$ F = \frac{m}{r}v^2 $$
So:
$$ F \propto v^2 $$
and a graph of $F$ against $v$ is a parabola. So far so good.
But now let's define a new variable $u = v^2$ so our equation becomes:
$$ F = \frac{m}{r}u $$
Now $F \propto u$ and if we draw a graph of $F$ against $u$ it will obviously be a straight line. You say:
and it's because when you plot $v^2$ on the $x$ axis, instead of just $v$, you are drawing the graph of $F$ against $u$ that I described above and it's a straight line.