[Physics] Why is the melting point of water independent of pressure

material-sciencephase-transitionpressure

I've read here that the boiling point of water is highly dependent on the pressure, whereas the melting point is independent of the pressure. Why is that? Is that true in general?

Best Answer

This is because of the Clausius-Clapeyron equation $$\frac{d \log T}{d \log P} = \frac{P \Delta V}{L}$$ where $T$ is the temperature of the phase transition, $\Delta V$ is the change in volume, and $L$ is the latent heat. The water/gas transition has an enormous $\Delta V$ because gas is much less dense than water, so $dT/dP$ is large. The water/ice transition has a $\Delta V$ about $10^{-3}$ as big, so $dT/dP$ is small.

Intuitively, there is some 'cost' $L$ to be paid doing the phase transition, and usually most of it is paid by thermal energy. But if the volume changes during the transition, the $P \Delta V$ work can also help, lowering the necessary temperature. So it makes sense that $dT/dP$ depends on the ratio of these two contributions.