Everything moves in geodesics if not acted on by a force other than gravity -- this is an axiom of general relativity (the geodesic equation). Geodesics are straight lines in the absence of gravity -- this is part of the other axiom of general relativity (the Einstein-Hilbert action, or the EFE or whatever).
Light doesn't interact much with everything, except quite weakly with gravity, and with some miscellaneous scattering patterns, like those which allow you to actually see things, but those are quite pointy (reflection, refraction, etc. -- the paths are pointy as long as the scattering boundary is sharp), so you still see a bunch of straight lines.
Yes, it's ok, but it's an explanation that has been stripped down to bare bones, and leaves out quite a bit. Here's a little more to help prop up the explanation.
First, it's important to realize that in a condensed phase like a solid or liquid the light is not interacting with molecules in isolation. Light is interacting with all of the molecules. This makes a big difference. Light absorbed and re-emitted by a single molecule can go off in (almost) any direction.
Next, remember that a photon is an excitation of a complete electromagnetic field. It is, unfortunately, often not helpful to think of a photon as a particle that exists at a particular place in space. Like all particles in quantum mechanics, there's a chance that it could exist anywhere. Individual interactions, on the other hand, can occur with a particular molecule at a particular location.
It's best to start thinking about your question in the realm of classical physics, and then modify it later to include quantum mechanics. Classically, when light interacts with a molecule, the electron is set into vibrational motion. The energy that the field gave to the molecule will stay with the molecule for a while while this oscillation occurs. The molecule, then, is a radiator and can generate its own light. That's the classical picture of the delay experienced by light during an interaction. After this re-emission, the light will travel at $c$.
How does it know to go straight? Here's where we need all the other molecules in the liquid. The incident field has a particular spatial pattern, say a sine pattern, and it excites in the molecules an oscillation pattern that exactly matches. The incident light was traveling in a particular direction with a well-defined phase front, and so too does the pattern of oscillation in the liquid. The light re-emitted from the molecules will also share that same pattern, although it will be delayed in time relative to the incident light. The re-emitted light adds to the portion of the incident light that passes unaffected. But the phase fronts, and hence the direction of travel, is parallel to that of the incident wave. It goes off in the same direction.
Photons: Almost the same story. Recall that a photon is an excitation of the light field. Instead of exciting the molecules into oscillation, the molecule temporarily absorbs a quantum of energy from the field (the "photon"), and the molecule is raised to an excited state. The molecule lives in this state for a short period of time, and then the energy is returned to the field ("photon emission"). But the business about phase fronts and directions still holds. The energy is added to a field propagating in the original direction, slightly delayed.
(Another detail we're leaving out. The absorption and re-emission I describe is a very fast process called "virtual transition". It is fast enough that the uncertainty principle $\Delta E \Delta t \leq \hbar/2$ allows energy conservation to be temporarily violated. So the frequency of the incident light does not have to match an absorption frequency of the molecule in this process, and the explanation works for transparent media.)
Note carefully that I refer to a photon as an excitation of the field, rather than as a particle. When the interaction between light and something else occurs at a particular place, as when it hits a particular pixel in a digital camera, it looks for all the world like a particle hit the pixel. But a more useful way of thinking about it is that the light field exists everywhere, but the interaction occurs at a particular place.
Hope that helps!
Best Answer
The Sun is so low to the horizon that it’s illuminating the high, wispy clouds from underneath. Where it’s dark, something (probably a cumulus cloud) is blocking that light.
The thin cloud in the resulting shadow is still there if you look closer, but it’s much harder to see because it’s not illuminated.
The line is so straight because Sun's light is just barely grazing the bottom of the wispy clouds. That line is the geometric projection of only the bit of the cloud that's throwing the shadow at just the right altitude.