The strings do not attach to the space-time manifold, they move around on it as a background. Option 1 is not right.
Option 2 is more like it, except that you are assuming that string theory as it is formulated in the string way builds up space-time from something more fundamental. This is not exactly true in the Polyakov formulation or in any of the string formulations (even string field theory). The string theory doesn't tell you how to build space-time from scratch, it is only designed to complete the positivist program of physics. It answers the question "if I throw a finite number of objects together at any given energy and momentum, what comes out?" This doesn't include every question of physics, since we can ask what happens to the universe as a whole, or ask what happens in when there are infinitely many particles around constantly scattering, but it's close enough for practical purposes, in that the answer to this question informs you of the right way to make a theory of everything too, but it requires further insight. The 1980s string theory formulations are essnetially incomplete in a greater way than the more modern formulations.
The only thing 1980s string theory really answers (within the domain of validity of perturbation theory, which unfortunately doesn't include strong gravity, like neutral black hole formation and evaporation) is what happens in a spacetime that is already asymptotically given to you, when you add a few perturbing strings coming in from infinity. It then tells you how these extra strings scatter, that is what comes out. The result is by doing the string perturbation theory on the background, and it is completely specified within string perturbation theory by the theory itself.
Option 3 is sort of the right qualitative picture, but I imagine you mean it as strings interacting with a quantum gravity field which is different from the strings, strings that deform space and then move in the deformed space. This is not correct, because the deformation is part of the string theory itself, the string excitations themselves include deformations of space-time.
This is the main point: if you start with the Polyakov action on a given background
$$ S = \int g_{\mu\nu} \partial_\alpha X^\mu \partial_\beta X^\nu h^{\alpha\beta} \sqrt{h} $$
Then you change the background infinitesimally, $g\rightarrow g+\delta g$, this has the effect of adding an infinitesimal perturbation to the action:
$$ \delta S = \int \delta g \partial X \partial X $$
with the obvious contractions. When you expand this out to lowest order, you see that the change in background is given by a superposition of insertion of vertex operators on the worldsheet at different propagation positions, and these insertions in the path-integral have the form
$$ \partial X^\nu \partial X^\mu$$
These vertex operators are space-time symmetric tensors, and these are the ones that create an on-shell graviton (when you smear them properly to put them on shell). So the changing background can be achieved in two identical ways in string theory:
- You can change the background metric explicitly
- You can keep the original background, and add a coherent superposition of gravitons as incoming states to the scattering which reproduce the infinitesimal change in background.
The fact that any operator deforming the world-sheet shows up as an on-shell particle in the theory, this is the operator state correspondence in string theory, tells you that every deformation of the background that can be long-range and slow deformation shows up as an allowed massless on-shell particle, which can coherently superpose to make this slow background change. Further, if you just do an infinitesimal coordinate transformation, the abstract path-integral for the string is unchanged, so these graviton vertex operators have to have the property that coordinate gravitons don't scatter, they don't exist as on-shell particles.
The reason this isn't quite "bulding space-time out of strings" is because the analysis is for infinitesimal deformations, it tells you how a change in background shows up perturbatively in terms of extra gravitons on that background. It doesn't tell you how the finite metric in space-time was built up out of a coherent condensation of strings. The question itself makes no sense within this formulation, because it is not fully self-consistent, it's only an S-matrix perturbative expansion. This is why the insights of the 1990s were so important.
But this is the way string theory includes the coordinate invariance of General Relativity. It is covered in detail in chapter 2 of Green Schwarz and Witten. The Ward identity was discovered by Yoneya, followed closely by Scherk and Schwarz.
The point is that the graviton is a string mode, a perturbation of the background is equivalent to a coherent superposition of gravitons, and graviton exchange in the theory includes the gravitational force you expect without adding anything by hand (you can't--- the theory doesn't admit any external deformations, since the world-sheet operator algebra determines the spectrum of the theory).
In the new formulations, AdS/CFT and matrix theory and related ideas, you can build up string theory spacetimes from various limits in such a way that you don't depend on perturbation theory, rather you depend on the asymptotic background being fixed during the process (so if it starts out flat, it stays mostly flat, if it starts out AdS, it stays AdS). This allows you to get a complete answer to the question of scattering on certain fixed backgrounds, and get different pictures of the same string-theory spectrum in terms of superficially completely unrelated gauge fields or matrix-models.
But you asked in the Polyakov string picture, and this is only consistent for small deformations away from a fixed background that satisfies the string equations of motion for the classical background.
Best Answer
The mass does depend on the state: it's a basic point of string theory that it gives a deeper derivation of properties of particles such as their masses and charges: they're derived from a deeper starting point. The mass of a particle is no longer a constant: it is an eigenvalue of an operator acting on the string. The set (spectrum) of possible masses of particles - that are fundamentally strings in a state - is calculated in an analogy with the spectrum of the Hydrogen atom or any other bound state in quantum mechanics.
Classically, the mass of a string would only be given by the tension times the length of the string (which is dynamical). Quantum mechanically, the mass also has contributions from the kinetic energy, because of the $E=mc^2$ equivalence between the mass and energy.
The squared mass operator for an open string is given by $$ m^2 = 2\pi T \sum_{n=1}^\infty \sum_{i=1}^{D-2} \alpha_{-n}^i \alpha_n^i $$ Here, $T$ is the tension of the string. The constant $2\pi T$ is usually written as $1/ \alpha'$ (read: "one over alpha prime") where $\alpha'$ is called the Regge slope.
The term $\alpha_{-n}^i \alpha_n^i$ is equal to $n$ times the integer-valued excitation level of the quantum harmonic oscillator associated with the $n$-th Fourier mode (standing wave) of the coordinate $X^i$ along the open string. As you can see, the squared mass is $2\pi T$ times an integer. That's the spectrum of open (bosonic) strings in the flat space.
For closed strings, the formula for $m^2$ has different factors of $2$ and contains sums over left-moving and right-moving oscillators. For superstrings, there are fermions and the integer may also be half-integer, with additional interesting technicalities.
See also: