Photoelectric Effect – Differences Between Work Function and Ionization Energy

ionization-energyphotoelectric-effect

In a particular textbook, the work function of a metal (in the context of the photoelectric effect) is defined as:

the minimum amount of energy necessary to remove a free electron from the surface of the metal

This sounds similar to ionisation energy, which is:

the amount of energy required to remove an electron from an atom or molecule in the gaseous state

These two energies are generally different. For instance, Copper has a work function of about 4.7eV but has a higher ionisation energy of about 746kJ mol-1 or 7.7eV.

I've sort of figured it's because the work function deals with free electrons whilst ionisation is done with a valence electron still bound within the atom. Is the difference due to the energy required to overcome the attraction of the positive nucleus?

Best Answer

The energies and Work functions of the elements named in the table above

There is definitely a relationship between the work function and ionisation energy of the elements. See the above figure in which I plotted the work functions (blue) and ionisation energies (yellow) of the elements named in the table of the former answer. ionisation vs Work

If you plot them against each other, it shows an definite, though loose, relationship. I bet there really is a relation between the two, but I do not know exactly what it is and why it exists.

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