Okay, so I looked up drag force equation, and I found that the equation involved the drag coefficient. Then I looked up the drag coefficient, and the equation for it involved the drag force. Eventually this loop stopped as I found this section on a Wikipedia page explaining how to find the drag coefficient of a specific shape. It all makes sense to me, but I don't understand some of the variables they defined to me, specifically the vectors (yes, I know about vectors, unit vectors, and dot products, but that's not what I'm asking). It might just be the fact that I haven't taken an AP physics class yet, but the variables don't seem to define the magnitudes of n or t. As well, by the way it's described, it seems î and n have the same direction, which can't be true or the dot product of t*î would be zero. And yes, I know, Wikipedia isn't always trustworthy 100% of the time (nothing is), but I've found that Wikipedia has, for the most part, provided accurate information regarding math and science. If you'd like to get a better reference for this topic, links to this Wikipedia page are down below (look in "Blunt and streamlined body flows"). If you know what these terms are supposed to mean, please explain to me.
[Physics] Variables in calculation of drag coefficient
aerodynamicsdragfluid dynamicsterminologyvectors
Related Solutions
The only way to determine the dynamics of the system (Newtonian fluid exerting a drag on a rigid object) in full generality, for all geometries and Reynolds numbers, is to solve the Navier-Stokes equations with the appropriate boundary conditions. These equations are at heart nothing more than local expressions for conservation of mass, momentum and energy underlying all of classical mechanics.
However, this is often more time-consuming than is warranted, since there exist far simpler expressions for drag that apply in certain geometrical and viscous limits. Even when your system does not precisely match the appropriate limiting conditions, you can often get a useful approximation by modeling your system as such. But if you need more accuracy, you can't avoid the full problem.
You've already mentioned one useful limit in your question. Another applies to the low-Reynolds number case, and is referred to as Stokes drag. Notice that in this case the drag is linearly proportional to the velocity, rather than proportional to the square of the velocity as in the high Reynolds number limit.
Given these two limits, one useful approach could be to write your drag force as $C_1 v$ + $C_2 v^2$ and then perform an empirical fit to find $C_1$ and $C_2$. You'll have to be careful, though, if you are working with non-steady flow, since $C_1$ and $C_2$ might then depend on time (note that this has already been pointed out in D.W.'s answer, but hopefully it is now more clear why this is often effective).
Caveat: If your fluid is non-Newtonian, then the situation can be even more complicated, since the simplest notion of viscous drag no longer applies.
OK so after some reading and research I have answered my question with the following - pseudo-code incoming:
// PHASE 1 - GRAVITY FOR THIS OBJECT
position = 0, 0, 0
mass = 1
gravity = 9.80665
fGrav = mass * gravity
// PHASE 2 - DRAG FOR THIS OBJECT
velocity = 0 // Object starts from rest
area = PI * (radius * radius)
airMassDensity = 1.204
dragForce = 0.5f * 0.47 * airMassDensity * Dot(velocity, velocity) * area
fDrag = -velocity.normalized * dragForce
// PHASE 3 - ACCUMULATE FORCES (TO BE USED IN CHANGE IN VELOCITY)
forces = fGrav + fDrag;
// PHASE 4 - UPDATE VELOCITY (TO BE USED IN CHANGE IN POSITION)
position += forces * timeDelta
In regards to my questions about calculating c which is the drag coefficient, that involved being a case of using some pre-calculated values, which for a sphere are readily available. I still wish to know how to calculate it for an object, but a lot of replies I got from people indicated its a pretty decent sized subject, and I would be well-advised to use those values available for things. Hope this helps someone in the future!
Best Answer
Here is the way in which you should interpret the different symbols:
Notice that the first term is the projection along the direction of motion $\widehat{\mathbf{i}}$ of integral of the normal component of the traction vector (the pressure) over the sphere (the rest of components are zero (on average) due to symmetry). This is the pressure drag.
Similarly, the second term represents the integral of the remaining components, also projected along the direction of motion. This is the friction (or skin) drag, which is due to viscous friction.