I've read that plane wave equations can be represented in various forms, like sine or cosine curves, etc. What is the part of the imaginary unit $i$ when plane waves are represented in the form
$$f(x) = Ae^{i (kx – \omega t)},$$
using complex exponentials?
Quantum Mechanics – Physical Significance of the Imaginary Part in Plane Waves $e^{i(kx-\omega t)}$
complex numberslinear systemsplane-wavequantum mechanicswaves
Best Answer
It doesn't really play a role (in a way), or at least not as far as physical results go. Whenever someone says
what they are really saying is something like
This looks a bit like the authors are trying to cheat you, or at least like they are abusing the notation, but in practice it works really well, and using exponentials really does save you a lot of pain.
That said, if you are careful with your writing it's plenty possible to avoid implying that $f(x) = Ae^{i(kx-\omega t)}$ is a physical quantity, but many authors are pretty lazy and they are not as careful with those distinctions as they might.
(As an important caveat, though: this answer applies to quantities which must be real to make physical sense. It does not apply to quantum-mechanical wavefunctions, which must be complex-valued, and where saying $\Psi(x,t) = e^{i(kx-\omega t)}$ really does specify a complex-valued wavefuntion.)