I started a mock paper for one of my entrance exams with this fairly easy question. I rearranged the equation and got 5/2, knowing that a diatomic molecule has a Cv of 5/2, i concluded that the answer must be either A or C, but I do not know the difference between rigid diatomic and non rigid diatomic, can someone explain the difference?
Best Answer
At sufficiently high temperature, a diatomic molecule may have a thermodynamic degree of freedom that corresponds to bond length oscillation. That would change the '5/2' to '6/2'.