When we have a spherical conducting shell and charge on outer surface of the shell then the potential inside remains constant i.e, kQ/R (R=radius). But say the inner surface of the shell is charged rather than outer then too does the potential remain constant?
Will the electric field still be 0 inside or will charges move towards outer surface , what would be the result ?
A situation similar to the one in the image below:-
Best Answer
If the grey and blue parts of your diagram are the conductors and the magnitudes of the two sets of charges are the same then you have drawn a correct diagram with an electric field present only in the region between the two sets of charges.
The field in that region being the same as if there was a $-Q$ charge at the centre of the arrangement. In all other regions, including outside the outer sphere, the electric field will be zero and there will be no charge resident on the outside of the outer sphere. Application of Gauss's law will show that is so.