So for a complex dielectric constant $\epsilon = \epsilon_a + i\epsilon_b$, the wave vector and index of refraction are related to it through $k = \frac{\omega}{c}n$ and $n = \sqrt{\frac{\mu \epsilon}{\mu_0 \epsilon_0}}$. According to Jackson, the real part of the dielectric is related to polarization and anomalous dispersion, while the imaginary part is associated with dissipation of energy into the medium.
If you write the wavevector as $k = \beta + i \alpha/2$ and plug it in the general wave formula (just in 1D right now) of $e^{ikr} = e^{-\alpha r/2}e^{i\beta r}$, the intensity drops as $e^{-\alpha r}$, so $\alpha$ is the attenuation constant, which tells you how quickly the wave dies out in the medium.
But, if you plug that form of $k$ into the above equations to solve for $\alpha$ and $\beta$ as a function of $\epsilon_a$ and $\epsilon_b$, you find that $\alpha$ and $\beta$ are both a function of both $\epsilon_a$ and $\epsilon_b$.
This is counterintuitive to me, because intuitively I'd think that the attenuation constant $\alpha$ would only be based on $\epsilon_b$, due to dissipation, and the same with $\beta$ and $\epsilon_a$.
Can anyone give a good physical explanation for this "mixing"?
Best Answer
There isn't really a good physical explanation - this simply arises from the conventions we choose to represent our electromagnetic fields.
The electric constant $\epsilon_0$ was defined as the constant needed to make Gauss's law for electricity and Coulomb's law work for whatever units of length, charge and force you want to choose. When we add a medium, we find it is useful to define the electric displacement vector and a new effective electric constant $\epsilon$ for that medium: $\epsilon$ accounts for the shifting of charge wrought by the electric field and the consequent "reaction field" from the bound charge: so we need to put $\epsilon$ into Gauss's law if we want it to work for the nett charge.
However, when you get to studying waves, you're putting together the Faraday and Ampère Laws (with Maxwell's "displacement current"): two different equations describing a different phenomenon than simply force and flux from an electric field. You have two first order coupled differential equations, so the speed and propagation constants depend on $\sqrt{\epsilon}$ and $\sqrt{\mu}$, because when you decouple second order equations you get square roots of the constant co-efficients involved in the arguments of the $\exp(i (k z - \omega t))$ basic solutions. If we had discovered waves first and Gauss's law second, we'd probably have defined things differently so that $\sqrt{\epsilon}$ and $\sqrt{\mu}$ were the more fundamental quantities. When you square or square root a complex quantity, you mix the components - that's all there is to it. You might even imagine defining $\epsilon^{\frac{1}{4}}$, $\mu^{\frac{1}{4}}$ as the fundamental quantities: this would be quite acceptable and you'd have squares of the fundamental quantities in Maxwell's equations. You'd still have mixing of real and imaginary components when you wanted to find the attenuation co-efficient. It's simply a matter of what conventions are used.