Update after @M. Enns's answer Consider a circular orbit of radius $a$ passing through the centre of a central force is given by the equation $r=2a\cos\theta$. Then using the orbit equation one can show that the force varies as $$\textbf{F}(|\textbf{r}|)=-\frac{k}{r^5}\hat{\textbf{r}}.\tag{1}$$
But an orbit passing through the centre of force O will have zero angular momentum when it passes through O, and nonzero when it doesn't pass through O. This shows that the angular momentum is changing throughout the motion. I wished to attach the figure but I couldn't. This problem is solved in the book Theoretical Mechanics by Spiegel.
But here is the fallacy. The angular momentum should be conserved for motion under any central force. However, this doesn't seem to work in this case. But the proof of conservation of angular momentum is based on the simple observation that $$\frac{d\textbf{L}}{dt}=\textbf{r}\times\textbf{F}=0\tag{2}$$ since $\textbf{F}=f(r)\hat{\textbf{r}}$ for any central force.
Is the proof (2) reliable at $r=0$ where the force (1) become singular?
Best Answer
I've looked at this problem, and the preceding pages in Spiegel's book, and it would seem to me that any particle travelling in this orbit would have an infinite velocity at O, at least if the velocity was non-zero anywhere else in the orbit since the potential is infinitely negative when r=0 so the kinetic energy would have to be infinite. Wouldn't it be the same situation as two massive particles moving towards each other until they are zero distance apart?
If that's right than your angular momentum at O becomes a zero times infinity situation...
Here's a Q&A from Quora that addresses a particle moving through the origin in central force motion.