The initial premise of your question is not, in general, correct.
Consider a 1000 kg car driving at a constant speed of 20 m/s around a flat circular racetrack with a radius of 500 meters. Note the constant speed: the car will take the same time to drive around the track, 157.1 seconds, hour after hour. The only change in the car's velocity is in the direction of the velocity, not its size. The only acceleration is the centripetal acceleration, and the only horizontal force needed is the centripetal force $$a_{cp}=\frac {v^2}{r}=0.8 \frac{m}{sec^2}$$ $$F_{cp}=m \times a_{cp}=800 \ newtons$$
The force exerted by the car's engine serves only to balance the various drag forces.
This force is supplied by the friction between the tires and the pavement; pour out some oil on the track to see what happens when the required centripetal force is not present!
The only acceleration is directed exactly towards the center of the circular track; there is no tangential acceleration. The car, at some moment, is travelling North at 20 m/s, and one half-circuit later, it is travelling South at the same speed. Clearly, it has accelerated.
Assume now that the driver presses on the brake pedal in a manner that she knows will bring the car to a stop in 40 seconds. There is now a tangential acceleration, at $-0.5 \frac{m}{sec^2}$, in addition to the centripetal acceleration above, and a tangential force of 500 newtons directed towards the back of the car. The total force needed from the tires is now the resultant of these two forces: 943.4 newtons directed around 32 degrees aft of inward. Touching the brakes could throw you into a skid! Of course, as the braking changes the car's speed, the centripetal force will decrease...
Though this question is old and has an accepted answer, I really don't feel the apparent confusion of terms and concepts in the question has been covered. Therefor let me add a try to clear this out.
In this case, the tension of the string acts as a centrifugal force that keeps the object moving in a circle.
Not centrifugal but centripetal.
- Centrifugal force is the feeling of being pushed outwards while in a circular motion (being pushed to the side of a car that turns).
- Centripetal force is the force (the resulting force) acting to keep an object in a circular motion. To do this, it must be pointing directly towards the center, perpendicular to the motion.
if centrifugal force is the only force acting on the object, why doesn't it collapse into the center? I am pretty sure this has to do with the object's inertia
Again, assuming you mean centripetal.
As mentioned above, the centripetal force is perpendicular to the motion. What happens when you move in one direction and is pulled to the side? This pull will pull you towards the center (towards the origin of the pull), only if you are standing still. If you are moving, then the pull will make you move towards the center, but at the same time you still move straight ahead. Your net movement is therefor not towards the center, but rather around it.
When you ask the question, you are making the mistake of connecting speed $\vec v$ directly with force $\vec F$. But remember that it should rather be $\vec a$ that is connected to $\vec F$. That means, force and velocity are not going in the same direction necessarily, only force and the change of velocity. And in this case, you change the radial velocity component, but keep the tangential velocity component constant - there is only acceleration (change of velocity) in the radial direction, but the net velocity is point in another way.
Also, what keeps the string taut during the swinging?
The explanation that the string is always taught is simple: The object doesn't move towards the center. When the centripetal force (the tension in the string) tries to pull the object closer, the object actually doesn't get closer. It only changes direction.
If you pull harder, then it will gain a larger radial acceleration, but since the speed must be kept constant (as there is no tangential acceleration to change the speed), the radius will change according to
$$a_{rad}=\frac{v^2}{r}$$
and the object comes closer. But if the force is just kept constant, then there is no change of radius during the motion.
There has to be some force countering the centripetal force that keeps the string tight.
No, why should there? I think you mix up the Newton's 1st and 2nd laws. The idea that counteracting forces must be present is when we have a situation of no acceleration; Newton's 1st law $$\sum \vec F=0$$
Then to reach a sum of $0$, all forces must be balanced by other forces. But since there is acceleration, namely radial acceleration in the direction of the centripetal force, then we must use Newton's 2nd law:
$$\sum \vec F=m\vec a$$
Here there is no requirement of a counteracting force to balance any other force. We just need force to cause this acceleration. And the centripetal force is doing exactly that: causing the radial acceleration.
but can a pseudo-force balance a real force?
No. Centrifugal force (not to confuse with centripetal force) is, as you point at, not a force. Just a "feeling" that you are being pushed out of the circle. Like when you are pushed to the side of car while turning. But this feeling is not a force, it is simply the acceleration that you feel. During a turn in a car, your body wants to just continue with the present speed and direction. The car then forces your body to follow along, and you are therefore pushed inwards by the car, which gives you the feeling of being squeezed into the side of the car.
Also, if centripetal were to be balanced by the pseudo-force, wouldn't the object not move at all (since the net force would be 0)?
Remember that it is not no motion but rather no acceleration (no change of speed) that is implied when the net force is zero. The speed should not be considered at all when looking at forces, and that is a key point to realize. Newton's 2nd law that combines forces with motion, is only connecting force with acceleration not with speed.
Best Answer
Let's review some basics.
A normal force means that part of the contact force between two objects (usually solids) that is directed perpendicular to the surface of contact. It's force will always be only as much as is needed to prevent the two object from occupying the same space.
A centripetal force is one that points toward the center of curvature. For objects whose motion is known (or constrained) to be along a prescribed curved path the net radial force will be exactly sufficient to provide the proper centripetal acceleration, which is $v_t^2/r$ (where $r$ is the radius of curvature and $v_t$ is the tangential velocity) on purely geometric grounds.
Now applying this understanding to the above problem.
You have correctly identified the two forces at work in the problem and weight and normal force (there may also be friction in a real case, but we're presumably ignoring that).
You write
which is incorrect because that vector sum may or may not be radial and the centripetal force is radial by definition. You may, however, identify that net force as a sum of the centripetal force and a tangential force.
As a consequence of the above misunderstanding, you suggest that at point B the normal force should point in some non-radial direction, but this is incorrect because the normal is perpendicular to the plane of contact which on a circle means radially.
I'm not sure why you suggest that the normal force at point C should be zero, but that is also wrong. The object is in curving motion and that means it has a centripetal acceleration. Gravity can't provide that acceleration because it point tangentially to the path at the point, so the whole centripetal acceleration is down to the normal force.
...
I'm not going to continue, because you should have something to work out the hard way, but the whole analysis rests on getting the behavior of the normal force and the nature of centripetal accelerations right. Always check with the basics.
Questions that might help you:
Does the object keep the same speed as it goes round the track? Why or why not? If not, what forces cause it to speed up or slow down? Can the normal force play a part in that?
Under what circumstances can a normal force be negative (that is tending to pull two object together)?