Energy – What Is the Maxwell Energy Distribution in One Dimension? Exploring Kinetic Theory

energykinetic-theory

Maybe my question is too specific but I could not find the answer.

Abstract from:

Yield Optimization and Time Structure of Femtosecond Laser Plasma
$\kappa \alpha$ Sources

The generation of femtosecond $\kappa \alpha$ x-rays from laser-irradiated plasmas is studied with a view to optimizing photon number and pulse duration. Using analytical and numerical models of hot electron generation and subsequent transport in a range of materials, it is shown that an optimum laser intensity $I_{opt}=7×10^9Z^{4.4}$ exists for maximum Kα yield. Furthermore, it is demonstrated that bulk targets are unsuitable for generating sub-ps x-ray pulses: instead, design criteria are proposed for achieving $\kappa \alpha$ pulse durations ≤ 100 fs using foils of $≈2μm$ thickness.

I have found in Yield Optimization and Time Structure of Femtosecond Laser Plasma
$\kappa \alpha$ Sources: PRL
one dimensional Maxwell energy distribution of electrons as

$f(E) dE =\frac{1}{\sqrt{EkT}}\exp\left(-\frac{E}{kT}\right) $

This expression diverges for $E\rightarrow 0$.

How one reaches to this expression I could not understand. Usually in 3D case the exponent is multiplied by $\sqrt{E}$.

I don't think that it is a typographical error

They have also written the total energy content as

$En=\int n f\left(E\right)E dE$

From dimensions of this expression it looks like the particle distribution per unit energy.

Is there a specific physical significance of $f\left(E\right)$

Please help.

Best Answer

Yes, there is. You can look here. It is the Maxwell-Boltzmann distribution of the energy per degree of freedom. This is a chi-square distribution and note that $$\int_0^\infty \frac{1}{\sqrt{EkT}}e^{-\frac{E}{kT}}dE= \frac{2}{\sqrt{kT}}\int_0^\infty e^{-\frac{x^2}{kT}}dx$$ that is finite as it should. The authors of the paper are somewhat cavaliers about normalization factors. Note also, that any power of $E$ grants a finite integral reducing to known Gaussian integrals.